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1 year ago

If one oscillation has 5.8 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?

1 answer:

7 0

If one oscillation has 5.8 times the energy of the second one of equal frequency and mass, 2.4:1 is the ratio of their amplitudes.

Oscillation is defined as the process of repeating fluctuations of a quantity or measure around its time equilibrium value. Oscillation can also be defined as the periodic fluctuation of matter between two values or about their average.

The definition of happiness is someone or something that makes you feel great joy or pleasure. An example of good luck is someone who wins the lottery. An example of happiness is a laughing baby. Besides making you feel better, positive emotions are good for your brain and body. It lowers stress hormones, relieves anxiety and depression, and strengthens the immune system. Feeling positive emotions every day has a huge impact on our well-being and health.

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Electric charges are either positive or ____

fenix001 [56]

Answer:

Negative

Explanation:

duh

4 0

3 years ago

Read 2 more answers

Suppose earth's mass increased but earth's diameter didn't change. Describe how the gravitational force between Earth and the ob

zheka24 [161]

Answer:

It increases proportionally

Explanation:

The gravitational force between the Earth and an object on its surface is given by

$F=G\frac{Mm}{R^2}$

where

G is the gravitational constant

M is the Earth's mass

m is the mass of the object

R is the Earth's radius

In this problem, the Earth's mass is increased, while the diameter (and therefore, the radius) doesn't change. From the equation, we see that the gravitational force is directly proportional to the Earth's mass: therefore, if the mass is increased, the force will increase as well by the same proportion (for example, if the mass is doubled, the force will double as well)

7 0

2 years ago

An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.

Aleksandr-060686 [28]

The tension in the upper rope is determined as 50.53 N.

<h3>Tension in the upper rope</h3>

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

T(u) is tension in upper rope
T(d) is tension in lower rope

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

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6 0

1 year ago

An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu

ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, $qE \times S + mg \times S = 0.5 \times mv^{2}$

$1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}$

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight and the above equation will be as follows.

$(1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2
}$

v = $sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}$

= 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0

2 years ago

If the crate shown here is moving at a constant speed in a straight line and the force applied is 310 N, what is the magnitude o

larisa86 [58]

Answer:

$f_k = 310N$

the answer is A.

Explanation:

Using the laws of newton:

∑F = ma

where ∑F is the sumatory of forces acting in the system, m the mass and a the acelertion of the system.

Then, if the block is moving with constant velocity, its aceleration is equal to 0, so:

∑F = m(0)

∑F = 0

It means that:

F - $f_k$ = 0

where F is the force applied and $f_k$ is the friction force. Replacing the value of F, we get:

310N - $f_k$ = 0

Finally, solving for $f_k$ :

$f_k = 310N$

8 0

3 years ago