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DedPeter [7]
3 years ago
14

When the height of the cylinder increased by a factor of 5from 100 m to 500 m, what happened to the cylinder's

Physics
1 answer:
Lesechka [4]3 years ago
6 0

Answer: It increased by a factor of 5

Explanation:

Gravitational potential energy P is given by the following formula:

P=mgh

Where:

m is the mass of the cylinder (assumed as constant)

g is the acceleration due gravity (assumed as constant)

h is the height of the cylinder

As we can see, P is directly proportional to h. Hence, if h increases by a factor of 5 P increases by a factor of 5, as well.

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A proton is held at rest in a uniform electric field. When it is released, the proton will lose?
nydimaria [60]

A proton is held at rest in a uniform electric field. When it is released, the proton will lose its kinetic energy.

Kinetic energy

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.

To learn more about kinetic energy refer here:

brainly.com/question/11301578

#SPJ4

5 0
1 year ago
Two charges, each of 2.9 microC are placed at two corners of a square 50cm on a side, If the charges are on one side of the squa
anyanavicka [17]

Answer:

The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

Explanation:

Given that,

First charge q_{1}= 2.9\mu C

Second chargeq_{2}= 2.9\mu C

Distance between two corners r= 50 cm

We need to calculate the electric field due to other charges at one corner

For E₁

Using formula of electric field

E_{1}=\dfrac{kq}{r'^2}

Put the value into the formula

E_{1}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\sqrt{2}\times10^{-2})^2}

E_{1}=52200=52.2\times10^{3}\ N/C

For E₂,

Using formula of electric field

E_{1}=\dfrac{kq}{r^2}

Put the value into the formula

E_{2}=\dfrac{9\times10^{9}\times2.9\times10^{-6}}{(50\times10^{-2})^2}

E_{2}=104400=104.4\times10^{3}\ N/C

We need to calculate the horizontal electric field

E_{x}=E_{1}\cos\theta

E_{x}=52.2\times10^{3}\times\cos45

E_{x}=36910.97=36.9\times10^{3}\ N/C

We need to calculate the vertical electric field

E_{y}=E_{2}+E_{1}\sin\theta

E_{y}=104.4\times10^{3}+52.2\times10^{3}\sin45

E_{y}=141310.97=141.3\times10^{3}\ N/C

We need to calculate the net electric field

E_{net}=\sqrt{E_{x}^2+E_{y}^2}

Put the value into the formula

E_{net}=\sqrt{(36.9\times10^{3})^2+(141.3\times10^{3})^2}

E_{net}=146038.69\ N/C

E_{net}=146.03\times10^{3}\ N/C

We need to calculate the direction of electric field

Using formula of direction

\tan\theta=\dfrac{141.3\times10^{3}}{36.9\times10^{3}}

\theta=\tan^{-1}(\dfrac{141.3\times10^{3}}{36.9\times10^{3}})

\theta=75.36^{\circ}

Hence, The magnitude of the electric field and direction of electric field are 146.03\times10^{3}\ N/C and 75.36°.

4 0
3 years ago
Convert 12cm to picometers​
Salsk061 [2.6K]

Answer:

1.2e+11

Explanation:

8 0
3 years ago
Read 2 more answers
Do you think there could be another period of time when so many brilliant discoveries are made in such a span of time? Why or Wh
Arada [10]

There won't be another period where many brilliant discoveries are made in such a span of time because of the high degree of advancement already.

<h3>What is Technology?</h3>

Tgis is defined as the application of scientific knowledge for practical purposes.

We have advanced technological advancement which is why there won't be many discoveries in such time span.

Read more about Technology hee brainly.com/question/7788080

8 0
1 year ago
Particles 1 and 2 each mass m fixed to the ends of a rigid massless rod of length L1 + l2 with L1 = 20cm and l2 = 80 cm. The rod
Degger [83]

Answer:

Sorry bro I don't even know the answer

7 0
3 years ago
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