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DedPeter [7]
3 years ago
14

When the height of the cylinder increased by a factor of 5from 100 m to 500 m, what happened to the cylinder's

Physics
1 answer:
Lesechka [4]3 years ago
6 0

Answer: It increased by a factor of 5

Explanation:

Gravitational potential energy P is given by the following formula:

P=mgh

Where:

m is the mass of the cylinder (assumed as constant)

g is the acceleration due gravity (assumed as constant)

h is the height of the cylinder

As we can see, P is directly proportional to h. Hence, if h increases by a factor of 5 P increases by a factor of 5, as well.

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How could the action force of a canoe moving through water be increased?.
BaLLatris [955]
There are several actions that can be used to increase the action force of a canoe that is moving through water. One can increase the rate of striking or strike harder than before with a bigger paddle. Using a lighter canoe can also be helpful for increasing the speed. I hope the answer comes to your help.
4 0
3 years ago
Which of these actions will increase friction? Select three options. Scratching a surface to make it rougher polishing a surface
k0ka [10]

Answer:

scratching a surface to make it rougher

increasing the size of a flying object

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Explanation:

5 0
2 years ago
Read 2 more answers
A man of mass 50kg ascends a flight of stairs 5m high in 5 seconds. If acceleration due to gravity is 10ms-2, the power expended
Setler79 [48]

The power expended is 500 W

Explanation:

First of all, we start by calculating the work done by the man in order to ascend: this is equal to the gravitational potential energy gained by the man, which is

W=mg\Delta h

where

m = 50 kg is the mass of the man

g=10 m/s^2 is the acceleration of gravity

\Delta h = 5 m is the change in height

Substituting,

W=(50)(10)(5)=2500 J

Now we can calculate the power expended, which is given by

P=\frac{W}{t}

where

W = 2500 J is the work done

t = 5 s is the time elapsed

Substituting, we find

P=\frac{2500}{5}=500 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

7 0
3 years ago
How much work must be done to stop a 1100-kg car traveling at 112 km/h?(Hint: You will need to convert the speed first.)Answer:
zimovet [89]

According to the Work-Energy Theorem, the work done on an object is equal to the change in the kinetic energy of the object:

W=\Delta K

Since the car ends with a kinetic energy of 0J (because it stops), then the work needed to stop the car is equal to the initial kinetic energy of the car:

K=\frac{1}{2}mv^2

Replace m=1100kg and v=112km/h. Write the speed in m/s. Remember that 1m/s = 3.6km/h:

\begin{gathered} K=\frac{1}{2}(1100kg)\left(112\frac{km}{h}\times\frac{1\frac{m}{s}}{3.6\frac{km}{h}}\right)^2=532,345.679...J \\  \\ \therefore K\approx532,346J \end{gathered}

Therefore, the answer is: 532,346 J.

5 0
1 year ago
A person has a mass of 60 kg. What is the person’s weight in Newtons and in pounds?
liubo4ka [24]

Answer:

137.2 in pounds and in Newton's it's 588.399

3 0
3 years ago
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