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DedPeter [7]
2 years ago
14

When the height of the cylinder increased by a factor of 5from 100 m to 500 m, what happened to the cylinder's

Physics
1 answer:
Lesechka [4]2 years ago
6 0

Answer: It increased by a factor of 5

Explanation:

Gravitational potential energy P is given by the following formula:

P=mgh

Where:

m is the mass of the cylinder (assumed as constant)

g is the acceleration due gravity (assumed as constant)

h is the height of the cylinder

As we can see, P is directly proportional to h. Hence, if h increases by a factor of 5 P increases by a factor of 5, as well.

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A) Give 3 examples of forces that are pulls and 3 examples that are pushes. b) For each example you give, state an approximate v
Stels [109]

Answer:

Explanation:

Force is defined as the push or pull which changes or tries to change the position, state of motion and the shape of the object.

(A) The examples of push are:

To push a chair on the floor, to push the car when it is stopped due to some problem, to push book on the table.

The examples of pull are :

To pull a chair towards you, to pull a string in a game of top, to pull the string in a gym.

(B) To push a chair or a book, the force required is small as compared to the to push a car.

To pull a chair or the string of top is less than the force to pull the string in gym.

7 0
2 years ago
A children’s roller coaster is released from the top of a track. If it’s maximum speed at ground level is 8 m/s, find the height
cupoosta [38]

Answer:

80 miles per 80 miles per hour so Likud those up So the kid throws up

4 0
3 years ago
A copper wire is 1.6 m long and its diameter is 1.1 mm. If the wire hangs vertically, how much weight (in N) must be added to it
qaws [65]

Answer:

Weight required = 194.51 N

Explanation:

The elongation is given by

            \Delta L=\frac{PL}{AE}

Length , L= 1.6 m

Diameter, d = 1.1 mm

Area

   A=\frac{\pi d^2}{4}=\frac{\pi \times (1.1\times 10^{-3})^2}{4}=9.50\times 10^{-7}m^2

Change in length, ΔL = 2.8 mm = 0.0028 m

Young's modulus of copper, E = 117 GPa = 117 x 10⁹ Pa

Substituting,

      \Delta L=\frac{PL}{AE}\\\\0.0028=\frac{P\times 1.6}{9.50\times 10^{-7}\times 117\times 10^9}\\\\P=194.51N

Weight required = 194.51 N

8 0
3 years ago
What is the name of the british scientist credited with discovering cathode rays?
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<span> </span>J. J. <span>Thomson discovered cathode rays</span>
5 0
3 years ago
What is potential energy?
iVinArrow [24]
energy associate with position or shape
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