Question

Two resistors with resistance values of 4.5 Ω and 2.3 Ω are connected in series or parallel

Answer 1

Explanation:

Given that,

Two resistors 4.5 Ω and 2.3 Ω .

Potential difference = 30 V

When they are in series, the current through each resistor remains the same. First find the equivalent resistance.

R' = 4.5 + 2.3

= 6.8 Ω

Current,

$I=\dfrac{V}{R'}\\\\I=\dfrac{30}{6.8}\\\\=4.41\ A$

So, the current through both lightbulb is the same i.e. 4.41 A.

When they are in parallel, the current divides.

Current flowing in 4.5 resistor,

$I_1=\dfrac{V}{R_1}\\\\=\dfrac{30}{4.5}\\\\I_1=6.7\ A$

Current flowing in 2.3 ohm resistor,

$I_2=\dfrac{V}{R_2}\\\\=\dfrac{30}{2.3}\\\\I_2=13.04$

In parallel combination, are brighter than bulbs in series.