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3 years ago

Two resistors with resistance values of 4.5 Ω and 2.3 Ω are connected in series or parallel

Physics

1 answer:

kenny6666 [7]3 years ago

5 0

Explanation:

Given that,

Two resistors 4.5 Ω and 2.3 Ω .

Potential difference = 30 V

When they are in series, the current through each resistor remains the same. First find the equivalent resistance.

R' = 4.5 + 2.3

= 6.8 Ω

Current,

$I=\dfrac{V}{R'}\\\\I=\dfrac{30}{6.8}\\\\=4.41\ A$

So, the current through both lightbulb is the same i.e. 4.41 A.

When they are in parallel, the current divides.

Current flowing in 4.5 resistor,

$I_1=\dfrac{V}{R_1}\\\\=\dfrac{30}{4.5}\\\\I_1=6.7\ A$

Current flowing in 2.3 ohm resistor,

$I_2=\dfrac{V}{R_2}\\\\=\dfrac{30}{2.3}\\\\I_2=13.04$

In parallel combination, are brighter than bulbs in series.

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Answer:

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3 years ago

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Answer:

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Solution:

As per the question:

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Now,

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where

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Thus

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3 years ago

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3 years ago

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Alecsey [184]

Answer:

Explanation:

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3 years ago