Answer:
A joule equals the amount of work done on an object when a force <u>of</u><u> </u><u>1</u><u> </u><u>Newton</u><u> </u> displaces that object <u>1</u><u> </u><u>metre</u>
Answer:
4.1 m
Explanation:
Given :
Mass of the block = m = 2 kg.
Initial velocity =
= 8 m/s
Angle of the incline = α = 30°
Coefficient of friction = μ = 0.35
Distance moved up the incline is calculated using the work energy theorem.
Work done by the net force = change in kinetic energy of the object.
Net work = work done by friction + work done by the gravity component.
(- mg sin 30 - μ mg cos 30 ) d = 
m cancels out when divided on both sides with m.
- [(9.8 sin 30 - ( 0.35 × 9.8 × cos 30) ] d = 1/2 ( 0² - 8² )
⇒ -7.87 d = -32
⇒ Distance traveled up the incline = d = 4.0658 m = 4.1 m
Answer:
235.8 N
Explanation:
Given that
Jack
83.5 east
Jill
93.3√2/2 east
93.3√2/2 north
Jane
121√2/2 east
121√2/2 south
From the above listed, we can calculate the total force component on x axis to be
Fx = 83.5 + 93.3√2/2 + 121√2/2
Fx = 83.5 + 65.97 + 85.56
Fx = 235 N (east)
Again, we calculate the total force component on y axis to be
Fy = 93.3√2/2 - 121√2/2
Fy = 65.97 - 85.56
Fy = -19.59 N (south)
Finding the resultant, we have
F = √(Fx²+Fy²)
F = √(235² + (-19.59)²)
F = √55225 + 383.7681
F = √55608.7681
F = 235.8 N
I believe the process you have described is known as an 'experiment'.