44.27 grams of CO2 is 1.0059 moles
as per given in the question,
the mass of is given as 44.27g
need to find how many moles are equal to 44.27g
The molar mass of 1 mole of
= Molar mass of C +2 x Molar mass of O
= 12 + 2 x 16
= 12 + 32 = 44 g
=> 44 gm of = 1 mole of
so, now 44.27 g of is equal to
i.e,
number of moles of =
number of moles of = 1.0059 moles
the number of moles of 44.27 grams of is 1.0059 moles
to learn more about similar questions:
Answer:
397 L
Explanation:
Recall the ideal gas law:
If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:
The left-hand side is simply some constant. Hence, we can write that:
Substitute in known values:
Solving for <em>V</em>₂ yields:
In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.
(Assuming 100 L has three significant figures.)
The volume of concentrated HCl : 2.073 ml
<h3>Further explanation</h3>Given
37% HCl by mass; density 1.19 g/mL
Required
The volume of concentrated HCl
Solution
Conversion to molarity :
37% x 1.19 g/ml =0.4403 g/ml
g/ml to mol/L :
=0.4403 g/ml x 1000 ml/L : 36.5 g/mol
=12.06 mol/L
or we can use formula :
Dilution formula :
M₁V₁=M₂V₂
12.06 M x V₁ = 0.1 M x 0.25 L
V₁ = 0.0021 L = 2.073 ml