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liraira [26]
3 years ago
9

PLS ANSWER FAST THANK UU

Chemistry
1 answer:
andriy [413]3 years ago
4 0
Answer
I think it might be B
Explanation
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Which statement describes how the binary ionic compound KBr is named?
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Which statement describes how the binary ionic compound KBr is named? The metal is named first, and the name is unchanged. Which of these is a property of a substance that is composed of atoms that are held together by ionic bonds?

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The low-resolution mass spectrum of an unknown analgesic X had a molecular ion of 151. Possible molecular formulas include C7H5N
garik1379 [7]

Answer:

The molecular formula of X is C8H9NO2

Explanation:

Step 1: Data given

exact mass of 151.0640

Molar mass of C = 12 g/mol

Molar mass of H = 1.00783 g/mol

Molar mass of O = 15.9949 g/mol

Molar mass of N = 14.0031 g/mol

Step 2: Calculate molar mass of C7H5NO3

7*12 + 5*1.00783 + 14.0031 + 3*15.9949 = 151.02695 g/mol

Step 3: Calculate molar mass of C8H9NO2

8*12 + 9*1.00783 + 14.0031 + 2*15.9949 = 151.06337 g/mol

Step 4: Calculate molar mass of C10H17N

10*12 + 17*1.00783 + 14.0031 = 151.13621 g/mol

The molecular formula of X is C8H9NO2

3 0
2 years ago
What energy is defined as the energy of motion
Veronika [31]

Answer:

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Use the expression we obtained in class to write the molar absorption coefficient of a particular transition in terms of the tra
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Answer:

Initially the function is symmetric with respect to the axis of the one dimensional box. In the final state it is also symmetrical, however you can envision a snapshot of the system as the light field is interacting with the wave-function wherein a node begins to develop as is shown in the middle and the wave function is evolving from the initial to final state. Now consider that the electron density during process is the square of the wave function:

Electron density during transition

As can be seen in the initial and final states the electron density is symmetrically distributed with respect to the axis of the box. However with the field on, the electron density is not symmetrically distributed and a transitory dipole moment can be present. To relate back to real molecules think of each of those orbitals as a linear combination of atomic orbitals. One important factor is the symmetry. But there may be one other factor that will be just as important as symmetry. If you treat orbital 1 as a linear combination over n orbitals and orbital 2 as a linear combinations of orbitals as well, there will be a spatial over lap between the orbital in the ground state and the orbital in the excited state. If there is no spatial overlap between the ground state and excited state orbitals there will be no transition dipole moment. However, if the electrons are in the same place spatially, a large transition dipole moment will result.

Explanation:

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What is the lowest atom on the periodic table
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It simply is the lowest in weight which is atoms.

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