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NeX [460]
3 years ago
8

Please help me with this question

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0

The mass of oxygen is 236.4 g.

Explanation:

To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.

First we calculate the molar weight of carbon dioxide:

molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2

molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole

Now we devise the following reasoning:

if in        44 g of CO₂ there are 32 g of oxygen

then in  325 g of CO₂ there are X g of oxygen

X = (32 × 325) / 44 = 236.4 g oxygen

Learn more about:

molar weight

brainly.com/question/9883301

#learnwithBrainly

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D. A broken piece of quartzite will break through, not around, quartz sand grains.

Quartzite and quartz sandstone have the <em>same chemical formula</em> (SiO_2)

Quartzite is a <em>metamorphic rock</em>. Heat and pressure have compressed the sand into a strong network of interlocking quartz grains.

Quartzite is so tough that it breaks through the sand grains rather than around them as in sandstone.

7 0
3 years ago
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Mrac [35]

Answer:

Energy level (n = 4), d subshell (l = 2)  

Step-by-step explanation:

The number in 4d tells you the energy level of the subshell: n = 4.

The letter d gives you the secondary quantum number l.

Depending on its value, the letter gives you the shape of the orbital.

l = 0 corresponds to an s orbital (spherical)

l = 1 corresponds to a p orbital (dumb-bell shaped)

l = 2 corresponds to a d orbital (four four-leaf clovers + one that looks like a dumbbell with a doughnut around its middle)

5 0
3 years ago
At constant temperature and pressure, increasing the amount of a gas will __________.
aivan3 [116]
At constant temperature and pressure, increasing the amount of gas will increase the volume.
6 0
3 years ago
All changes saved
Kipish [7]

Answer:

4.00L

Explanation:

Using Charle's law, which have the following equation:

V1/T1 = V2/T2

Where;

V1 = initial volume (litres)

T1 = initial temperature (Kelvin)

V2 = final volume (litres)

T2 = final temperature (Kelvin)

According to the information provided, T1 = 275K, T2 = 400K, V1 = ?, V2 = 5.82L

Hence, using the formula;

V1/275 = 5.82/400

400 × V1 = 275 × 5.82

400V1 = 1600.5

V1 = 1600.5 ÷ 400

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4 0
3 years ago
How many grams of potassium bromide, KBr, are in 100mL of a 0.50 M solution?
VMariaS [17]

Answer:

5.95g

Explanation:

1 dm^{3} = 1000 mL

∴ 100 mL = 100 ÷ 1000 = 0.1 dm^{3}

Volume = <u>0.1 </u>dm^{3}<u />

Concentration = <u>0.5 M</u>

Concentration = \frac{No. of moles}{volume}

0.5 = \frac{x}{0.1}

No. of moles = 0.5 x 0.1 = <u>0.05 moles</u>

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Mass in 1 mole of KBr = 39 + 80 = 119g (39 is the mass of potassium and 80 is the mass of bromine)

0.05 = \frac{x}{119}

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