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NeX [460]
3 years ago
8

Please help me with this question

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
6 0

The mass of oxygen is 236.4 g.

Explanation:

To find the mass of oxygen in 325 g of carbon dioxide (CO₂) we follow the next algorithm.

First we calculate the molar weight of carbon dioxide:

molar weight of CO₂ = molar weight of carbon × 1 + molar weight of oxygen × 2

molar weight of CO₂ = 12 × 1 + 16 × 2 = 44 g/mole

Now we devise the following reasoning:

if in        44 g of CO₂ there are 32 g of oxygen

then in  325 g of CO₂ there are X g of oxygen

X = (32 × 325) / 44 = 236.4 g oxygen

Learn more about:

molar weight

brainly.com/question/9883301

#learnwithBrainly

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5 0
3 years ago
How many grams are in 32.2 L of CO2?
Naddika [18.5K]

Answer:

63.25 grams of CO₂

Explanation:

To convert from liters to grams, we first need to convert from liters to moles. To do this, we divide the liters by 22.4, the amount of liters of a gas per mole.

32.2 / 22.4

= 1.4375 moles of CO₂

Now we want to convert from moles to grams. To do this, we multiply the moles by the molar mass of CO₂. The total molar mass can be found on the periodic table by adding up the molar mass of carbon (12) and two oxygen (32).

12 + 32 = 44

Now we want to multiply the moles by the molar mass.

1.4375 • 44

= 63.25 grams of CO₂

This is your answer.

Hope this helps!

7 0
3 years ago
What are the half-reactions for a galvanic cell with Zn and Mg electrodes?
Alona [7]

the half-reactions

cathode : Zn²⁺ (aq) + 2e⁻ ---> Zn (s)  

anode : Mg (s) → Mg²⁺ (aq) + 2e−

a balanced cell reaction

Zn²⁺(aq) + Mg(s)→ Zn(s) + Mg²⁺ (aq)

<h3 /><h3>Further explanation</h3>

Given

Zn and Mg electrodes

Required

The half-reactions for a galvanic cell

Solution

To determine the reaction of a voltaic cell, we must determine the metal that serves as the anode and the metal that serves as the cathode.

To determine this, we can either know from the standard potential value of the cell or use the voltaic series

1. voltaic series

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent

So the metal on the left will easily undergo oxidation and function as anode

Since Mg is located to the left of Zn, then Mg functions as anode and Zn as a cathode

2. Standard potentials cell of Mg and Zn metals :

Mg2+ + 2e– → Mg E° = -2,35 V

Zn2+ + 2e– → Zn E° = -0,78 V

The anode has a smaller E°, then Mg is the anode and Zn is the cathode.

7 0
3 years ago
Scientific Method
Leona [35]

Answer:

Problem,  Variables,  Hypothesis,  Research,  Procedure,  Data, Conclusion.

Explanation:

First, you have to know what the problem that you're talking about is. Then, you have to know the independent, dependent, and controlled variables are in order to make a hypothesis. Then do research about the topic. After that, you make the procedure your experiment, if that's what your doing. Then after the experiment, you find the data. Using that data, you make a conclusion.

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The compound dinitrogen trioxide would have<br> the chemical formula?
Lelechka [254]

Answer:

The answer is N203 Dinitrogen trioxide.

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