Answer:
The nucleus is the most densely compacted part of the atom, it is in the center circled by the electron cloud or shells. It is filled with positively charged protons, and neutrons which have no charge. It is smaller than the electron cloud in size, but in quantity it has more subatomic particles since protons and electrons are equal and the nucleus has nuetrons
The correct answer is B.
Strong acids completely dissociates to give hydrogen ions . Weak bases can only partially dissociate to give hydroxide ions .
Therefore when equal amounts of acid and base are mixed, while Acid is completely dissociated and gives out hydrogen ions but base only gives out a fraction of hydroxide ions.
Therefore number of hydrogen ions in the solution will be higher than hydroxide ions, resulting in an acidic pH. Therefore pH <7
Answer:
<h2>The first thing to do here is to use the molarity and the volume of the initial solution to figure out how many grams of copper(II) chloride it contains.</h2><h2 /><h2>133</h2><h2>mL solution</h2><h2>⋅</h2><h2>1</h2><h2>L</h2><h2>10</h2><h2>3</h2><h2>mL</h2><h2>⋅</h2><h2>7.90 moles CuCl</h2><h2>2</h2><h2>1</h2><h2>L solution</h2><h2>=</h2><h2>1.051 moles CuCl</h2><h2>2</h2><h2 /><h2>To convert this to grams, use the compound's molar mass</h2><h2 /><h2>1.051</h2><h2>moles CuCl</h2><h2>2</h2><h2>⋅</h2><h2>134.45 g</h2><h2>1</h2><h2>mole CuCl</h2><h2>2</h2><h2>=</h2><h2>141.31 g CuCl</h2><h2>2</h2><h2 /><h2>Now, you know that the diluted solution must contain </h2><h2>4.49 g</h2><h2> of copper(II) chloride. As you know, when you dilute a solution, you increase the amount of solvent while keeping the amount of solute constant.</h2><h2 /><h2>This means that you must figure out what volume of the initial solution will contain </h2><h2>4.49 g</h2><h2> of copper(II) chloride, the solute.</h2><h2 /><h2>4.49</h2><h2>g</h2><h2>⋅</h2><h2>133 mL solution</h2><h2>141.32</h2><h2>g</h2><h2>=</h2><h2>4.23 mL solution</h2><h2>−−−−−−−−−−−−−− </h2><h2 /><h2>The answer is rounded to three sig figs.</h2><h2 /><h2>You can thus say that when you dilute </h2><h2>4.23 mL</h2><h2> of </h2><h2>7.90 M</h2><h2> copper(II) chloride solution to a total volume of </h2><h2>51.5 mL</h2><h2> , you will have a solution that contains </h2><h2>4.49 g</h2><h2> of copper(II) chloride.</h2>
Answer:
The concentration of hydroxide ions is 3.02*10⁻³ M
Explanation:
The pOH (or OH potential) is a measure of the basicity or alkalinity of a contamination and is defined as the negative logarithm of the activity of the hydroxide ions. That is, the concentration of OH- ions:
pOH= -log [OH-]
The pOH has a value between 0 and 14 in aqueous solution, the solutions with pOH being greater than 7 being acidic, and those with pOH less than 7 being basic.
If pOH= 2.52 then
2.52= -log [OH-]
[OH-]= 3.02*10⁻³ M
<u><em>The concentration of hydroxide ions is 3.02*10⁻³ M</em></u>
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