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hram777 [196]
3 years ago
7

Is coffee and water heterogeneous or homogeneous?​

Chemistry
1 answer:
stepan [7]3 years ago
5 0

Answer:

coffee is a homogeneous mixture while water is a heterogeneous mixture

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The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air
IceJOKER [234]

Answer:

1.75\cdot 10^{-4} M

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

S = k_H p^o

Where k_H is Henry's law constant.

Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

S_1 = 2.67\cdot 10^{-4} M

Also, at sea level, we have an atmospheric pressure of:

p = 1.00 atm

Given mole fraction:

\chi_{O_2} = 0.209

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

p^o = \chi_{O_2} p

Then the equation becomes:

S_1 = k_H \chi_{O_2} p

Solve for k_H:

k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

p = 0.657 atm

Apply Henry's law using the constant we found:

S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M

8 0
3 years ago
Predict the geometry about each interior atom in acetic acid:
aleksandr82 [10.1K]

The atomic structure of the acetic acid is:

                        H     O

                        l       l

                H – C – C – O – H

                        l

                        H

 

We can see from the structure that there are 2 interior atoms, and these are all Carbon atoms.


The geometry is:

Tetrahedral on First Carbon

Trigonal Planar on Second Carbon

5 0
3 years ago
ccording to all known laws of aviation, there is no way a bee should be able to fly. Its wings are too small to get its fat litt
drek231 [11]

Answer:

The bee's energy output can be calculated directly, and related to its size. it only needs enough air resistance to counter its weight and enough power in its wings to sustain this resistance. it bee like that.

4 0
3 years ago
A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both sol
Scorpion4ik [409]

Answer:

see explanation

Explanation:

Step 1: Data given

Volume of 1M CusO4 = 50.0 mL = 0.05 L

Volume of 2M KOH = 50.0 mL = 0.05 L

Temperature before mixing= 17.8 °C

Temperature after mixing = 32.4 °C

The heat capacity of the calorimeter is 12.1 J/K

Step 2: The balanced equation

CuSO4(aq)+ 2KOH(aq) →Cu(OH)2(s) + K2SO4(aq)

Step 3: Calculate mass of the solution

Suppose the density of the solution is 1 g/mL

Total volume = 100 mL

Mass of the solution = density * volume

Mass of the solution = 1g/mL * 100 mL = 100 grams

Step 4:

Q = m*c*ΔT

with m = the mass of the solution = 100 grams

with c= the heat capacity of the solution = 4.184 J/g°C

with ΔT = 32.4 - 17. 8 = 14.6 °C

Q = 6108.64 J

Step 5: Calculate the energy of the calorimeter

Q = c*ΔT

Q = 12.1 J/K * 14.6

Q = 176.66 J

Step 6: Calculate total heat

Qtotal = 6108.64 + 176.66 = 6285.3 J = 6.29 kJ (negative because it's exothermic)

Step 7: Calculate moles

Moles CuSO4 = 0.05 L * 1M = 0.05 moles

Moles KOH = 0.05 L * 2M = 0.10 moles

ΔH = -6.29 kJ / 0.05 moles = -125.8 kJ/mol

3 0
3 years ago
The activiation energy required for a chemical reaction can be decreased by?
ollegr [7]

Answer:

C)

Explanation:

C) adding a catalyst to the reaction.

5 0
3 years ago
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