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irina1246 [14]
3 years ago
10

Hydrochloric acid is the primary component of gastric juice in the stomach (see Chemistry in Action: GERD-Too Much Acid or Not E

nough? on p. 299 in the textbook). The reaction between hydrochloric acid and the carbonate ion, the primary active ingredient in antacid tablets such as TUMS®,can be written as HCl(aq)+CO2−3(aq)⇌HCO−3(aq)+Cl−(aq)

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
8 0

Answer:

Acid: HCl(aq), conjugate base: Cl⁻(aq)

Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)

The rewrite reaction is shown below.

Explanation:

The acid compound is the one that loses an H⁺, and the compound formed when it happens is its conjugate base. The base compound is the acceptor of H⁺, and its conjugate acid is the compound formed (Brosted-Lowry theory).

So, the acid-base pairs are:

Acid: HCl(aq), conjugate base: Cl⁻(aq)

Base: CO₃⁻²(aq), conjugate acid: HCO₃⁻(aq)

The TUMS® is an antacid, so it intends to reduce the concentration of the strong acid HCl. So, the forward reaction is favored. It can be represented with the forward arrow larger than the reversible arrow, as shown in the image below.

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Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:

48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ

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Luke stirred the water during the experiment. How did this make his results more reliable?
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Is ketchup made of one paratical
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4 years ago
1.) which of these is the balanced equation for this reaction?
horsena [70]

Answer:

1.D) CH4 + 2O2 → CO2 + 2H2O

2C)2,1,2

3.D)SIO2 + 4HF → SIF4 + 2H2O

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6 0
3 years ago
Ethanol melts at -114 degree C. The enthalpy of fusion
Brut [27]

Answer: The heat required is 6.88 kJ.

Explanation:

The conversions involved in this process are :

(1):ethanol(s)(-135^0C)\rightarrow ethanol(s)(-114^0C)\\\\(2):ethanol(s)(-114^0C)\rightarrow ethanol(l)(-114^0C)\\\\(3):ethanol(l)(-114^0C)\rightarrow ethanol(l)(-50^0C)

Now we have to calculate the enthalpy change.

\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]

where,

\Delta H = enthalpy change = ?

m = mass of ethanol = 25.0 g

c_{p,s} = specific heat of solid ethanol= 0.97 J/gK

c_{p,l} = specific heat of liquid ethanol = 2.31 J/gK

n = number of moles of ethanol = \frac{\text{Mass of ethanol}}{\text{Molar mass of ethanol}}=\frac{25.0g}{46g/mole}=0.543mole

\Delta H_{fusion} = enthalpy change for fusion = 5.02 KJ/mole = 5020 J/mole

T_{final}-T_{initial}=\Delta T = change in temperature

The value of change in temperature always same in Kelvin and degree Celsius.

Now put all the given values in the above expression, we get

\Delta H=[25.0 g\times 0.97J/gK\times (-114-(-135)K]+0.534mole\times 5020J/mole+[25.0g\times 2.31J/gK\times (-50-(-114))K]

\Delta H=6885.93J=6.88kJ     (1 KJ = 1000 J)

Therefore, the heat required is 6.88 kJ

3 0
3 years ago
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