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jasenka [17]
1 year ago
14

During August, the average cost of gasoline was $3.22 per gallon. During September, the average cost of gasoline was $3.67 per g

allon. Suppose the cost of gasoline is expected to rise by the same percentage with each passing month. Select the response that is true.
Mathematics
1 answer:
Lorico [155]1 year ago
4 0
To ensure the proper number amount to the bond make sure that you multiply using the numerator and the denominator as well as check over the passage because you dont know how much to use according to the results so the answers should be

(B)
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Step-by-step explanation:relax and claculate in ur mine

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Why does the quotient of 8 ÷ 1 not change when we add a place value in the dividend and the divisor to make 80 ÷ 10?
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Answer:

Basically this is because division can be thought of as how many times does the divisor have to be multiplied in order to produce the dividend.

So you would need to multiply 1 8 times in order to produce the dividend,

Similarly, 10 goes into 80 8 times. The zeros are simply cancelled out in the division.

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PLEASE HELP
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3 years ago
A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0
yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

P(x

Where, for example, P(0) and P(1) are calculated as:

P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098

Then, P(x, so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)

Where, for example, P(4) is calculated as:

P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001

Then, P(x\geq4 )=0.3504, so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0
4 years ago
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