Why is molarity important?

Chemistry

1 answer:

Debora [2.8K]1 year ago

5 0

<h2>Answer</h2>

• To determine whether a particular solution is ,concentrated ,or ,diluted

• To determine the ,actual concentration ,of a solution

<h2>Explanations:</h2>

When a chemical is added to a solution, chemical solutions are formed. Molarity is used in expressing the concentration of a solution. Molarity is the ratio of the number of moles of a solute to the volume of its solution.

<h2>Importance of molarity</h2>

Molarity is important to determine whether a particular solution is concentrated or diluted. It is also used to determine the actual concentration of a solution

Hence, to determine the concentration of any solution, the moles of the element and its volume in solution are required.

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If the half life of a radioactive isotope is 1 day, then how much of the original isotope remains at the end of two days?

ikadub [295]

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25%

Explanation:

In a half life of a radioactive isotope is 1 day,it means it loses its half mass each day

We a formula for N half life

$\sf { \frac{1}{2} }^{n}$

where n is the number of days

Here the isotope is kept for 2 days

so it's left over mass will be

$\sf { (\frac{1}{2}) }^{2} \\ \\ \\ \frac{1}{2} \times \frac{1}{2} \\ \\ \sf \frac{1}{4}$

It's left over mass 1/4th of the original mass

Now, we need to find it's percentage by multiplying with 100

$\sf \frac{1}{4} \times 100 \%\\ \\ \sf \cancel\frac{100}{4} \% \\ \\ \sf 25\%$

So 25% mass will be left after 2 day of half life radioactive isotope.

8 0

2 years ago

Read 2 more answers

a calorimeter contained 75.0 g of water at 16.95 C. A 93.3-g sample of iron at 65.58 C was placed in it, giving a final temperat

Nostrana [21]

Answer:- $\frac{382.69J}{0C}$ .

Solution:- Mass of Iron added to water is 93.3 g. Initial temperature of iron metal is 65.58 degree C and final temperature of the system is 19.68 degree C.

temperature change, $\Delta T$ for iron metal = 65.58 - 19.68 = 45.9 degree C

specific heat for the metal is given as 0.444 J per g per degree C.

let's calculate the heat lost by iron metal using the equation:

$q=mc\Delta T$

where, q is the heat energy, m is mass, c is specific heat and delta T is change in temperature. let's plug in the values and calculate q for iron metal:

$q=93.3g(45.9^0C)(\frac{0.444J}{g.^0C})$