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aleksklad [387]
2 years ago
14

If the half life of a radioactive isotope is 1 day, then how much of the original isotope remains at the end of two days?

Chemistry
2 answers:
ikadub [295]2 years ago
8 0

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25%

Explanation:

In a half life of a radioactive isotope is 1 day,it means it loses its half mass each day

We a formula for N half life

\sf  { \frac{1}{2} }^{n}

where n is the number of days

Here the isotope is kept for 2 days

so it's left over mass will be

\sf { (\frac{1}{2}) }^{2}  \\  \\  \\  \frac{1}{2}  \times  \frac{1}{2}  \\  \\  \sf  \frac{1}{4}

It's left over mass 1/4th of the original mass

Now, we need to find it's percentage by multiplying with 100

\sf  \frac{1}{4}  \times 100 \%\\  \\  \sf   \cancel\frac{100}{4} \% \\  \\  \sf 25\%

<u>So</u><u> </u><u>2</u><u>5</u><u>%</u><u> </u><u>mass</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>2</u><u> </u><u>day</u><u> </u><u>of</u><u> </u><u>half</u><u> </u><u>life</u><u> </u><u>radioactive</u><u> </u><u>isotope</u><u>.</u><u> </u>

JulijaS [17]2 years ago
8 0
25% because the half life of 100 is 50 and the half life of 50 is 25
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which of the following testable questions will provide evidence that elements in the same group have similar properties?
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The testable question which will provide evidence that elements in the same group have similar properties is valency

<h3>What is the valency?</h3>

In essence, how many electrons are present in their outermost shell.

Valency and Groups in the periodic table, elements are arranged in order of their atomic numbers and hence, the periodic table is a systematic arrangement of elements in an array of vertical columns called Groups and horizontal arrays called Periods.

  • Complete question here:

which of the following testable questions will provide evidence that elements in the same group have similar properties A. Valency B. Orbit C. Group D. Period

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Learn more on Groups and Valency:

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A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
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\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

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❍ Molecular weight of \sf{CaCO_3}

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⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

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