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3 years ago

Can liquid CO2 exist on Earth? Why or Why not ?

Chemistry

1 answer:

Zanzabum3 years ago

6 0

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

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Name at least two benefits of using models in science

STatiana [176]

Answer:

Viewing systems from multiple perspectives.

Discovering causes and effects using model tractability.

Improving system understanding through visual analysis.

Explanation:

Got this from google, lol. But, I put three here just in case you could get extra credit for more than two.

3 0

3 years ago

Read 2 more answers

A sample of basalt has smaller crystals than a sample of granite. What is the most likely reason for this?

posledela

The most likely reason is that basalt is an extrusive rock, while granite is an intrusive rock. What this means is that basalt forms at the surface of the earth, where temperatures are cooler. Because of the cooler external temperature, basalt cools relatively quickly, and there isn't as much time for mineral crystals within the rock to align to form larger crystals while the rock is cooling. Granite, on the other hand, forms below the surface of the earth, where temperatures are significantly higher. Therefore, it doesn't cool as quickly, and the minerals within granite have more time to form larger crystals and the rock cools.

4 0

3 years ago

I NEED HELP ASAP PLEASE

scZoUnD [109]

I think it’d be C. I’m not 100% if it is tho

8 0

3 years ago

Obsidian _____.

Romashka-Z-Leto [24]

Answer:

has large mineral crystals

6 0

2 years ago

Read 2 more answers

Fatty acids spread spontaneously on water to form a monomolecular film. A solution containing 0.10 mm^3 of a fatty acid is dropp

lara31 [8.8K]

Divide the volume by the area. Using scientific makes things a bit cleaner.

$0.10\,\mathrm{mm}^3 = 10^{-1}\,\mathrm{mm}^3$

$400.\,\mathrm{cm}^2 = 4\times10^2\,\mathrm{cm}^2$

Then

$\dfrac{10^{-1} \,\mathrm{mm}^3}{4\times10^2\,\mathrm{cm}^2} \cdot \dfrac{\left(\frac{1\,\rm m}{10^3\,\rm mm}\right)^3}{\left(\frac{1\,\rm m}{10^2\,\rm cm}\right)^2} = \dfrac{10^{-1}\times10^{-9} \,\mathrm m^3}{4\times10^2\times10^{-4}\,\mathrm m^2} = \dfrac{10^{-10}}{4\times10^{-2}}\,\mathrm m \\\\ ~~~~~~~~= 0.25\times10^{-8}\,\mathrm m$

Now, 1 m = 10⁹ nm, so

$0.25 \times10^{-8}\,\mathrm m \cdot \dfrac{10^9\,\rm nm}{1\,\rm m} = 0.25\times10^1\,\mathrm{nm} = \boxed{2.5\,\rm nm}$

8 0

1 year ago