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2 years ago

7

A balanced chemical equation has the same number and type of atoms in the reactants as compared to the products. An unbalanced c

hemical equation does not. True or false?

1 answer:

amid [387]2 years ago

5 0

False because they both have different properties

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If the H+ in a solution is 1x10^-1 mol/L what is the OH-

damaskus [11]

PH scale is used to determine how acidic or basic a solution is.
we have been given the hydrogen ion concentration. Using this we can calculate pH,
pH = - log[H⁺]
pH = - log (1 x 10⁻¹ M)
pH = 1
using pH can calculate pOH
pH + pOH = 14
pOH = 14 - 1
pOH = 13
using pOH we can calculate the hydroxide ion concentration
pOH = - log [OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 10⁻¹³ M
hydroxide ion concentration is 10⁻¹³ M

8 0

3 years ago

The decomposition of mercury (ii) oxide at high temperature, is it an endothermic or exothermic process? Write a chemical reacti

gulaghasi [49]

Answer:

that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy

Explanation:

hope it helped u buddy

6 0

2 years ago

Read 2 more answers

Which of the following statements about the elements in group 2 of the periodic table is true?

stiks02 [169]

Answer:

they all have two electrons in their outermost shell

8 0

2 years ago

Select the Newman projection that corresponds to the following molecule 2. Select the choice that best describes the relationshi

OverLord2011 [107]

The relationship of a pair of compounds could be one between these options :
- Structural isomerisms
happened when molecules with same molecular formula have bonded together in different orders
- Stereoisomerism
Happened when two or more compounds differing only in the spatial arrangement of their atom

hope this helps

4 0

2 years ago

Read 2 more answers

const2013 [10]

Answer:

$\large \boxed{\text{-1276 kJ/mol}}$

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

CH₃CH₂OH + 3O₂ ⟶ 2CO₂ + 3H₂O

Bonds: 5C-H 1C-C 1C-O 1O-H 3O=O 4C=O 6O-H

D/kJ·mol⁻¹: 413 347 358 467 495 799 467

$\Delta H = \sum{D_{\text{reactants}}} - \sum{D_{\text{products}}}\\\sum{D_{\text{reactants}}} = 5 \times 413 + 1 \times 347 + 1 \times 358 + 1 \times 467 + 3 \times 495 = 3237 + 1485\\=\text{4722 kJ}\\\sum{D_{\text{products}}} = 4 \times 799 + 6 \times 467 =3196 + 2802 = \text{5998 kJ}\\\Delta H = 4722 - 5998= \textbf{-1276 kJ} \\ \text{The overall energy change is $\large \boxed{\textbf{-1276 kJ/mol}}$}.$

6 0

3 years ago