La respuesta es la letra b
Answer:
Hydrogen will undergo nuclear fusion
,
Explanation:
here, it is being explained:-
The first thing that will inevitably arise would be that nuclear fusion would arise with hydrogen.
When fuel from the larger star's outer shell piles up on the white dwarf's surface, the temperature and density continuously increase as a result of which hydrogen will undergo nuclear fusion.
Explanation:
We'll need two equations.
v² = v₀² + 2a(x - x₀)
where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.
x = x₀ + ½ (v + v₀)t
where t is time.
Given:
v = 47.5 m/s
v₀ = 34.3 m/s
x - x₀ = 40100 m
Find: a and t
(47.5)² = (34.3)² + 2a(40100)
a = 0.0135 m/s²
40100 = ½ (47.5 + 34.3)t
t = 980 s
The toy rocket is launched vertically from ground level, at time t = 0.00 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 72 m and acquired a velocity of 30 m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground with negligible air resistance.
The total energy of the rocket, which is a sum of its kinetic energy and potential energy, is constant.
At a height of 72 m with the rocket moving at 30 m/s, the total energy is m*9.8*72 + (1/2)*m*30^2 where m is the mass of the rocket.
At ground level, the total energy is 0*m*9.8 + (1/2)*m*v^2.
Equating the two gives: m*9.8*72 + (1/2)*m*30^2 = 0*m*9.8 + (1/2)*m*v^2
=> 9.8*72 + (1/2)*30^2 = (1/2)*v^2
=> v^2 = 11556/5
=> v = 48.07
<span>The velocity of the rocket when it impacts the ground is 48.07 m/s</span>
1 watt = 1 joule per second
1 joule = 1 newton-meter
1 newton = 1 kg-meter per second²
Put it all together and you have . . .
1 watt = 1 <em>kg-meter² / second³
</em>
