a) The net force on the system is 883.5 N
b) The tension in the rope is 505.5 N
c) The applied force is 1875.8 N
Explanation:
a)
We start by considering the whole system snowmobile+sled. We can apply Newton's second law:
where
is the net force on the system
m = 150 kg is the mass of the sled
M = 315 kg is the mass of the snowmobile+rider
is the acceleration
Substiting the values into the equation, we find the net force:
b)
Now we consider only the forces acting on the sled. Again, we apply Newton's second law:
where:
T is the tension in the rope, which pulls the sled forward
is the frictional force acting on the sled, which acts backward
m = 150 kg is the mass of the sled
is the acceleration
The force of friction on the sled is given by
where
is the coefficient of friction of the sled on ice
m = 150 kg
is the acceleration of gravity
Substituting and solving for T, we find:
c)
Now we consider instead the forces acting on the snowmobile+rider only. Applying again Newton's second law,
where
F is the applied force, which pushes the snowmobile forward
is the force of friction acting backward on the snowmobile
T = 505.5 N is the tension in the rope, which pulls the snowmobile backward
M = 315 kg is the mass of the snowmobile+rider
is the acceleration
The force of friction on the snowmobile is given by
where
is the coefficient of friction of the snowmobile on ice
m = 315 kg
Substituting and solving for F, we find the applied force:
Learn more about Newton's second law:
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