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harina [27]
3 years ago
12

Las carreras de velocidad pura en el atletismo son:

Physics
1 answer:
zheka24 [161]3 years ago
8 0
La respuesta es la letra b
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Mrs. Paul and Dr. Mykannen ride a tandem bike on the beach. They ride along the beach for about 455 meters. Their final velocity
algol [13]

Answer:

Time = 80.91 seconds

Explanation:

Given the following data;

Velocity = 5.50 m/s.

Distance = 445 meters

To find the time;

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

Velocity = \frac{distance}{time}

Substituting into the formula, we have;

5.5 = 445/time

Time = 445/5.5

Time = 80.91 seconds

5 0
3 years ago
how does the electric force between two charged particles change if the distance between them is increased by a factor of 3? a.
Aleksandr [31]

how does the electric force between two charged particles change if the distance between them is increased by a factor of 3?

a. it is reduced by a factor of 3

4 0
3 years ago
As Aubrey watches this merry-go-round for a total of 2 minutes, she notices the black horse pass by 15 times. What is the period
Hunter-Best [27]
Periodic time is the time taken for one complete oscillation by a body in circular motion. In this case the merry-go round takes 2 minutes to cover 15 complete oscillations. 2 Minutes = 120 seconds
Hence, 15 oscillations takes 120 secs
         thus 1 oscillation takes 120/15 = 8 seconds
therefore the period of the merry-go-round = 8 seconds
8 0
3 years ago
Read 2 more answers
Can someone give me an objective and subjective statement example please
shusha [124]

Answer:

Objective: It is raining. Subjective: I love the rain!

Explanation:

Anything objective sticks to the facts, but anything subjective has feelings. Objective and subjective are opposites.

(Hope this helps can I pls have brainlist (crown)☺️)

7 0
2 years ago
a car moving with a speed of 10 metre per second is accelerator at the rate of 2 metre per second square find its velocity after
STatiana [176]

a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )

2 = ( v(2) - 10 ) ÷ ( 6 - 0 )

2 × 6 = v(2) - 10

v(2) = 12 + 10

v(2) = 22 m/s

7 0
3 years ago
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