Ask question

Ask question

All categories

3 years ago

11

To remove 700 j of heat from a refrigerator, the compressor in the refrigerator does 500 j of work. How much heat is released in

to the surrounding room

1 answer:

Vinvika [58]3 years ago

7 0

If the compressor removes 500 j if the 700 the 200 j left would have Ben conducted through the refrigerator/200 j released into the room

You might be interested in

The cornea of the eye has a radius of curvature of approximately 0.40 cm , and the aqueous humor behind it has an index of refra

My name is Ann [436]

Answer:

0.64814 cm

Explanation:

$n_1$ = Refractive index of air = 1

$n_2$ = Refractive index of aqueous humor = 1.35

u = Object distance = $\infty$

v = Image distance = 25 mm

R = Radius of curvature of the cornea

Lens equation

$\dfrac{n_2-n_1}{R}=\dfrac{n_1}{u}+\dfrac{n_2}{v}\\\Rightarrow \dfrac{1.35-1}{R}=\dfrac{1}{\infty}+\dfrac{1.35}{2.5}\\\Rightarrow \dfrac{1.35-1}{R}=\dfrac{1.35}{2.5}\\\Rightarrow \dfrac{0.35}{R}=\dfrac{1.35}{2.5}\\\Rightarrow R=\dfrac{0.35\times 2.5}{1.35}\\\Rightarrow R=0.64814\ cm$

Radius of curvature of the cornea is 0.64814 cm

5 0

4 years ago

When an 81.0-kg adult uses a spiral staircase to climb to the second floor of his house, his gravitational potential energy incr

kap26 [50]

Assuming both staircases are of equal height from the ground floor, then the nature of the staircase does not change the gravitational potential energy.

We can, from information given, find the height of the floor, and then apply to the child using the standard formula, E=mgh.

However, in this case, it is a matter of proportions, i.e.

81.0 kg : 2.25 kJ

17.5 kg : x kJ

cross multiply to get

x=2.25*17.5/81=0.486 kJ (or 486 J) to three significant figures.

3 0

3 years ago

Which of the following describes resistance force?

Verdich [7]

Force applied by the machine to over come resistance

5 0

3 years ago

Read 2 more answers

Highlight each sentence that is true about atoms, matter, and electric charge.

lisov135 [29]

Answers B and D are true.

7 0

3 years ago

A person eats a container of strawberry yogurt. The Nutritional Facts label states that it contains 255 Calories (1 Calorie = 41

Sever21 [200]

Answer:

mass = 0.44 Kg

Explanation:

given,

Calories contain in the strawberry yogurt = 255 calories

1 Calorie = 4186 J

latent heat of vaporization = 2.42 x 10⁶ J/Kg

mass of perspiration = ?

Energy = 255 calories

Energy = 255 x 4186

= 1067430 J

Energy = mass x latent heat of vaporization

$mass = \dfrac{Q}{L_v}$

$mass = \dfrac{1067430}{2.42 \times 10^6}$

mass = 0.44 Kg

4 0

4 years ago