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PilotLPTM [1.2K]
4 years ago
7

An engine extracts 452.8kJ of heat from the burning of fuel each cycle, but rejects 266.7 kJ of heat (exhaust, friction,etc) dur

ing each cycle. What is the thermal efficiency of the engine?
Physics
1 answer:
Svetlanka [38]4 years ago
7 0

Answer: The thermal efficiency of the engine is 41.09 %.

Explanation:

Efficiency is the ratio of the useful work performed to the total energy expended or heat taken in.

Formula for thermal efficiency of engine is

\eta=1- \frac{Q_2}{Q_1}\times 100

\eta = efficiency

{Q_2} = heat rejected = 266.7 kJ

{Q_1} = heat extracted = 452.8 kJ

Putting in the values we get:

\eta=1- \frac{266.7 kJ}{452.8 kJ }\times 100

\eta=0.41\times 100

\eta =41.09\%

The thermal efficiency of the engine is 41.09 %.

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What is the difference between folk dance and ballroom dance
disa [49]

Answer:

folk dancing is old music and ball room is young dancing

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3 years ago
A severe thunderstorm, known as a supercell, forms. It begins in an area where cold, dry, polar air meets warm, moist, tropical
alexdok [17]

Answer:

A tornado can, surprisingly, cause a supercell, so the answer would be C.) tornado

Explanation:

When cold, dry, and polar air meet warm, moist tropical air, the atmosphere becomes unstable causing a supercell.

Final Answer:

C.) tornado

Afterthought:

<em>Please give BRAINLEST!</em>

Thanks,

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8 0
3 years ago
Read 2 more answers
What is the ideal banking angle for a gentle turn of 1.20-km radius on a highway with a 105 km/h speed limit (about 65 mi/h), as
Mnenie [13.5K]

Answer:

4.14°

Explanation:

given:

r = 1.2 km

v = 105 km/h

1) <em>convert your given </em>

a) r = 1.2 km to m = 1200m

b) v = 105 km/h  to m/s = 29.2 m/s

2) <em>plug into your ideal banking angle equation</em>

tan^-1(\frac{v^2}{rg}) = \frac{29.2^2}{(1200)(9.8)} = 4.14°

8 0
3 years ago
A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is
ivanzaharov [21]
<span>anwser will be 

F = ma

where 

F = force exerted on the bullet 
m = mass of the bullet = 5 gm (given) = 0.005 kg. 
a = acceleration of the bullet 

Substituting appropriately, 

F = 0.005a --- call this Equation 1 

Next working equation is 

Vf^2 - Vo^2 = 2as 

where 

Vf = velocity of the bullet as it leaves the muzzle = 326 m/sec (given) 
Vo = initial velocity of bullet = 0 
a = acceleration of bullet 
s = length of the rifle's barrel 

Substituting appropriately, 

326^2 - 0 = 2(a)(0.83) 

a = 64,022 m/sec^2 

the anwser will be
Substituting this into Equation 1, 

F = 0.005(64,022) 

F =320.11 Newtons 

Hope this helps. </span><span>
</span>
8 0
3 years ago
How much heat is absorbed by 41 g iron skillet when its temperature varies from 9°C. to 20°C
alexgriva [62]

Answer:

202.95J

Explanation:

The formulae for the energy absorbed by the iron skillet is;

q=m*c*ΔФ   where q=energy absorbed, m is mass of iron skillet, c is specific heat capacity and ΔФ is change in temperature

Given that;

m= 41g

ΔФ=20°-9°=11°

c=0.45 J/g°C

q= 41×0.45×11

q= 202.95 J

4 0
3 years ago
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