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3 years ago

Why is the position vs. time graph for an object in free fall a curve?

1 answer:

7 0

Under free fall, the object is falling with a velocity that is increasing uniformly. Since the gradient of position-time graph reflects the velocity, the gradient is increasing, i.e. curve.

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The air in a room has a mass of 50kg and a specific heat of 1,000 J/(kg.C). What is the change in the thermal energy of the air

dem82 [27]

<span>We know the change of thermal energy is proportional to the specific heat of the matter, its mass and the change of temperatures, according the following formula: Q = C*m*(Tf-Ti) where: Q is the heat added or removed (in joules, J) C is the specific heat of the matter, in our case air 1,000 J/(Kg*C) m is the mass, in our case 50 kg of air Tf is final temperature Ti is initial temperature then: Q = 1000 * 50 * (30-20) = 500,000 Joules That means that 500,000 joules need to be added to increase temperature of the room 10 ÂşC (from 20 to 30 ÂşC)</span>

5 0

4 years ago

Please help and show workings. <br>

Mnenie [13.5K]

Effective resistance = 2+1.5 = 3.5 ohms

Current in the circuit = 1.2 A

Lost volts in the battery = 1.8V

Current in one of the 3 ohms resistors = 0.6 A

I hope it helps

3 0

3 years ago

A Cessna aircraft has a liftoff speed of 120 km/h What minimum constant acceleration does the aircraft require to be airborne af

Lady_Fox [76]

Answer:

Explanation:

Using the equation of motion v² = u²+2aS

v is the final velocity = 120km/hr

120km/hr = 120 * 1000/1 * 3600 = 33.3m/s

u is the initial velocity = 0m/s

a is the acceleration

S is the distance covered = 240m

On substituting the given parameters

33.3² = 0²+2a(240)

33.3² = 480a

1110 = 480a

a = 1110/480

a = 2.3125m/s²

Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²

4 0

4 years ago

19. The work done by a magnetic field on a charged particle moving in it is:

Tresset [83]

Answer:

The work done by a magnetic feild on a chraged particle moving in it is zero

4 0

4 years ago

Based on Newton's law of motion, which combination of rocket bodies and engine will result in the acceleration of 40 m/s ^2 at t

ad-work [718]

The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body Mass (gram) Engine Force (newtons)

1 500 1 25

2 1500 2 20

3 750 3 30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

20 = 0.5 x acceleration

Acceleration $=\frac{20}{0.5}$

$=\frac{200}{5}$

$= 40 \ m/s^2$

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of $40 \ m/s^2$ at the start of the launch.

8 0

3 years ago