Hey there!
We know that a chemical reaction is balanced when there is the same amount of each element on both sides of the equation.
According to the law of conservation of mass, matter cannot be created or destroyed, so we must have the same amount of each element on each side of a chemical equation.
We count the amount of each element on each side, and the products should have the same number as the reactants.
Hope this helps!
<h3>Mass of CO₂ generated from the combustion : 14.277 kg</h3><h3>Further explanation</h3>
Mass Heptane : 0.348 x 17 = 5.916 kg
mass C in Heptane (MW=100.21 g/mol) :
![\tt \dfrac{7.12}{100.21}\times 5.916=4.959~kg](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B7.12%7D%7B100.21%7D%5Ctimes%205.916%3D4.959~kg)
Mass Nonane : 0.101 x 17 = 1.717 kg
mass C in Nonane (MW=128.2 g/mol) :
![\tt \dfrac{9.12}{128.2}\times 1.717=1.446~kg](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B9.12%7D%7B128.2%7D%5Ctimes%201.717%3D1.446~kg)
Mass Octane : 0.551 x 17 = 9.367 kg
mass C in Otane (MW=114.23 g/mol) :
![\tt \dfrac{8.12}{114.23}\times 9.367=7.872~kg](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B8.12%7D%7B114.23%7D%5Ctimes%209.367%3D7.872~kg)
Total mass produced :
4.959+1.446+7.872=14.277 kg
The mass is
Explanation:
First, we need to find the volume of the cube.
v = lwh
v = (4)(4)(4)
v = 64 cubic cm
Now, since we know the volume and the density, we can figure out the mass.
The formula is mass = volume x density
Mass = 64 x 2.7
Mass = 172.8 g.
Therefore, the mass is 172.8 grams.
Electrons and protons: 20
Neutrons: 20.078
Answer:
mass = 1.8x10⁻³ kg; number of moles = 4.1x10⁻⁵ kmol; specific volume = 0.55 m³/kg; molar specific volume = 24.4 m³/kmol
Explanation:
By the Avogadro's number, 1 mol of the matter has 6.02x10²³ molecules, thus, the number of moles (n) is the number of molecules presented divided by Avogadro's number:
n = 2.5x10²²/6.02x10²³
n = 0.041 mol
n = 4.1x10⁻⁵ kmol
The molar mass of CO₂ is 44 g/mol (12 g/mol of C + 2*16g/mol of O), and the mass is the number of moles multiplied by the molar mass:
m = 0.041 mol * 44 g/mol
m = 1.804 g
m = 1.8x10⁻³ kg
The specific volume (v) is the volume (1L = 0.001 m³) divided by the mass, and it represents how much volume is presented in each part of the mass:
v = 0.001/1.8x10⁻³
v = 0.55 m³/kg
The molar specific volume (nv) is the volume divided by the number of moles, and it represents how much volume is presented in each part of the mol:
nv = 0.001/4.1x10⁻⁵
nv = 24.4 m³/kmol