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1 year ago

What percent is 24 out of 36

Mathematics

1 answer:

AURORKA [14]1 year ago

8 0

Answer:

66.67

Step-by-step explanation:

(24*100)/36

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Find the unknown length of x

nlexa [21]

25 is the length of x, using the 30-60-90 special triangle method

8 0

3 years ago

An article regarding interracial dating and marriage recently appeared in the Washington Post. Of the 1,709 randomly selected ad

VMariaS [17]

Answer:

The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

323 blacks, 86% of blacks said that they would welcome a white person into their families. This means that $n = 323, p = 0.86$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.86 - 1.96\sqrt{\frac{0.86*0.14}{323}} = 0.8222$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.86 + 1.96\sqrt{\frac{0.86*0.14}{323}} = 0.8978$

The 95% confidence interval for the percent of all black adults who would welcome a white person into their families is (0.8222, 0.8978).

5 0

3 years ago

Function f is differentiable and decreasing for all real numbers. If y=f(2x^3 - 3x^2), for which of the following intervals of x

vichka [17]

Answer:

The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.

4 0

2 years ago

You are designing a miniature golf course and need to calculate the surface area and volume of many of the objects that will be

laiz [17]

a. To solve the first part, we are going to use the formula for the surface area of a sphere: $A=4 \pi r^2$
where
$A$ is the surface area of the sphere
$r$ is the radius of the sphere
We know from our problem that $r=5ft$ ; so lets replace that value in our formula:
$A=4 \pi (5ft)^2$
$A=314.16ft^2$

To solve the second part, we are going to use the formula for the volume of a sphere: $V= \frac{4}{3} \pi r^3$
Where
$V$ is the volume of the sphere
$r$ is the radius
We know form our problem that $r=5ft$ , so lets replace that in our formula:
$V= \frac{4}{3} \pi (5ft)^3$
$V=523.6ft^3$

We can conclude that the surface area of the sphere is 314.16 square feet and its volume is 523.6 cubic feet.

b. To solve the first part, we are going to use the formula for the surface area of a square pyramid: $A=a^2+2a \sqrt{ \frac{a^2}{4} +h^2}$
where
$A$ is the surface area
$a$ is the measure of the base
$h$ is the height of the pyramid
We know form our problem that $a=8ft$ and $h=12ft$ , so lets replace those value sin our formula:
$A=(8ft)^2+2(8ft) \sqrt{ \frac{(8ft)^2}{4} +(12ft)^2}$
$A=266.39ft^2$

To solve the second part, we are going to use the formula for the volume of a square pyramid: $V=a^2 \frac{h}{3}$
where
$V$ is the volume
$a$ is the measure of the base
$h$ is the height of the pyramid
We know form our problem that $a=8ft$ and $h=12ft$ , so lets replace those value sin our formula:
$V=(8ft)^2 \frac{(12ft)}{3}$
$V=256ft^3$

We can conclude that the surface area of our pyramid is 266.39 square feet and its volume is 256 cubic feet.

c. To solve the first part, we are going to use the formula for the surface area of a circular cone: $A= \pi r(r+ \sqrt{h^2+r^2}$
where
$A$ is the surface area
$r$ is the radius of the circular base
$h$ is the height of the cone
We know form our problem that $r=5ft$ and $h=8ft$ , so lets replace those values in our formula:
$A= \pi (5ft)[(5ft)+ \sqrt{(8ft)^2+(5ft)^2}]$
$A=226.73ft^2$

To solve the second part, we are going to use the formula for the volume os a circular cone: $V= \pi r^2 \frac{h}{3}$
where
$V$ is the volume
$r$ is the radius of the circular base
$h$ is the height of the cone
We know form our problem that $r=5ft$ and $h=8ft$ , so lets replace those values in our formula:
$V= \pi (5ft)^2 \frac{(8ft)}{3}$
$V=209.44ft^3$

We can conclude that the surface area of our cone is 226.73 square feet and its surface area is 209.44 cubic feet.

d. To solve the first part, we are going to use the formula for the surface area of a rectangular prism: $A=2(wl+hl+hw)$
where
$A$ is the surface area
$w$ is the width
$l$ is the length
$h$ is the height
We know from our problem that $w=6ft$ , $l=10ft$ , and $h=16ft$ , so lets replace those values in our formula:
$A=2[(6ft)(10ft)+(16ft)(10ft)+(16ft)(6ft)]$
$A=632ft^2$

To solve the second part, we are going to use the formula for the volume of a rectangular prism: $V=whl$
where
$V$ is the volume
$w$ is the width
$l$ is the length
$h$ is the height
We know from our problem that $w=6ft$ , $l=10ft$ , and $h=16ft$ , so lets replace those values in our formula:
$V=(6ft)(16ft)(10ft)$
$V=960ft^3$

We can conclude that the surface area of our solid is 632 square feet and its volume is 960 cubic feet.

e. Remember that a face of a polygon is a side of polygon.
- A sphere has no faces.
- A square pyramid has 5 faces.
- A cone has 1 face.
- A rectangular prism has 6 faces.
Total faces: 5 + 1 + 6 = 12 faces

<span>We can conclude that there are 12 faces in on the four geometric shapes on the holes.
</span>
f. Remember that an edge is a line segment on the boundary of the polygon.
- A sphere has no edges.
- A cone has no edges.
- A rectangular pyramid has 8 edges.
- A rectangular prism has 12 edges.
Total edges: 8 + 20 = 20 edges

Since we have 20 edges in total, we can conclude that your boss will need 20 brackets on the four shapes.

g. Remember that the vertices are the corner points of a polygon.
- A sphere has no vertices.
- A cone has no vertices.
- A rectangular pyramid has 5 vertices.
- A rectangular prism has 8 vertices.
Total vertices: 5 + 8 = 13 vertices

We can conclude that there are 0 vertices for the sphere and the cone; there are 5 vertices for the pyramid, and there are are 8 vertices for the solid (rectangular prism). We can also conclude that your boss will need 13 brackets for the vertices of the four figures.

7 0

3 years ago

4: Jason buys 2 baseball bats for $300 . What is the unit rate per bat ?

Katena32 [7]

Answer:

$150

Step-by-step explanation:

3 0

3 years ago