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qaws [65]
2 years ago
5

Determine the limiting reactant in each of the following reactions:

Chemistry
1 answer:
wolverine [178]2 years ago
3 0

The reactant in a chemical process known as the limiting reactant controls how much product can be produced. When the limiting reactant is completely used up, the reaction will come to an end.

<h3>Find the limiting reactant ?</h3>
  • As a result of 1 mol Sb4O6 reacting with 6 mol H2SO4, only 0.1 mol Sb4O6 reacts with 0.6 mol H2SO4, leaving only 0.5 mol H2SO4. This indicates that H2SO4 is the limiting reactant and Sb4O6 is present in excess.
  • According to your equation, which is balanced, 0.1 mol Sb4O6 should react with 0.6 mol H2SO4, yet there is only 0.5 mol H2SO4 on hand.
  • Therefore, only.083 mol of Sb4O6 are reacted.
  • The reactant that is present in the limiting amount—the limiting reactant—determines the extent to which a chemical reaction occurs.
  • The trick is really quite easy! We employ an augmented matrix to hold the data derived from the balancing equation Sb4O6 + 6H2SO4 --> 2Sb2(SO4)3 + 6H2O.
  • Although you are provided 0.5 mol of H2SO4, the reaction requires 0.6 mol. Therefore, the limiting reactant is H2SO4.
  • Only 0.0833 mol of Sb4O6 is required, but you have 0.1 mol. Sb4O6 is therefore the extra reactant.

To learn more about limiting reactant refer to:

brainly.com/question/27986321

#SPJ1

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What is the mass in grams of carbon dioxide that would be required to react with 75.8 g of LiOH in the following chemical reacti
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69.6 g CO₂

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To find the mass of carbon dioxide, you need to (1) convert grams LiOH to moles LiOH (via molar mass from periodic table values), then (2) convert moles LiOH to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (desired unit in the numerator). The final answer should have 3 sig figs to reflect the given value's sig figs.

Molar Mass (LiOH): 6.9410 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (LiOH): 23.947 g/mol

2 LiOH(s) + 1 CO₂(g) ----> Li₂CO₃(s) + H₂O(l)

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

75.8 g LiOH          1 mole             1 mole CO₂               44.007 g
------------------  x  ----------------  x  -----------------------  x  -------------------  =
                            23.947 g         2 moles LiOH              1 mole

= 69.6 g CO₂

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