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Elena L [17]
3 years ago
11

What is the weight in grams of 3.36 x 10^23 molecules of Copper Sulfate?

Chemistry
1 answer:
Bas_tet [7]3 years ago
7 0
 <span>(3.36x10^23 molecules ÷ 6.02x10^23 molecules)(159.62 g/mol) = 89.1 g</span>
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describe in general terms an experiment to determine the molal freezing point depression constant kf of water. Assume the availa
Dvinal [7]
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There ya have it!
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