False a cation is formed when it losses an electron.
The answer for this problem is only 3-methylcyclohex-1-ene. When
trans- 1- bromo- 2-methylcyclohexane is exposed to dehydrohalogenation, the formation
formed is 3-methyl-1-cyclohexene. The explanation for the changed products of
these two reactions can be explained by sketching suitable reaction mechanisms.
Answer:
18.8 g
Explanation:
The equation of the reaction is;
AgClO3(aq) + LiBr(aq)------>LiClO3(aq) + AgBr(s)
Number of moles of AgClO3 = 117.63 g/191.32 g/mol = 0.6 moles
Number of moles of LiBr = 10.23 g/86.845 g/mol = 0.1 moles
Since the molar ratio is 1:1, LiBr is the limiting reactant
Molar mass of solid AgBr = 187.77 g/mol
Mass of precipitate formed = 0.1 moles * 187.77 g/mol
Mass of precipitate formed = 18.8 g
Put the mixture in water, the pebbles will sink, the pepper will float, and the sugar will dissolve
Answer:
The molar mass is 138.8843 g/mol
