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2 years ago

Order the atoms from largest to smallest: Cs , Si , Sn .

Chemistry

1 answer:

dimaraw [331]2 years ago

4 0

Answer:

Si, Sn, Cs

Explanation:

Atomic no. Atomic radius

Silicon Si_______14___________0.117
Tin Sn______50___________0.140
cesium Cs______55___________0.262

Silicon is the smallest among these

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Consider the reaction below. HI + H2O mc014-1.jpg H3O+ + I– Which is an acid-conjugate base pair? HI and H2O H2O and H3O+ H3O+ a

lesya692 [45]

Answer: Option (d) is the correct answer.

Explanation:

According to Bronsted-Lowry, species which donate a proton are known as acid. The species which accept a proton are known as a base.

In the given reaction, acids and bases are as follows.

HI + $H_{2}O$ $\rightarrow$ $H_{3}O^{+}$ + $I^{-}$

Acid Base Conjugate acid Conjugate base

Therefore, the acid HI loses a proton to form a conjugate base that is $I^{-}$ .

Thus, we can conclude that HI and $I^{-}$ is an acid conjugate base pair.

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3 years ago

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Another simple question and I need it bad

podryga [215]

Oh this is extremely hard...i might just die lol jk its the last one measuring cylinder :)

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2 years ago

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Air, with an initial absolute humidity of 0.016 kg water per kg dry air, is to be dehumidified for a drying process by an air co

amid [387]

Answer:

(a) The proportion of dry air bypassing the unit is 14.3%.

(b) The mass of water removed is 1.2 kg per 100 kg of dry air.

Explanation:

We can express the proportion of air that goes trough the air conditioning unit as $p_{d}$ and the proportion of air that is by-passed as $p_{bp}$ , being $p_{d}+p_{bp}=1$ .

The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:

$0.004 = 0.016*p_{bp}+ 0.002*p_{d}$

Replacing the first equation in the second one we have

$0.004 = 0.016*(1-p_{d})+ 0.002*p_{d}=0.016-0.016*p_{d}+0.002*p_{d}\\0.004 - 0.016 = (-0.016+0.002)*p_{d}\\-0.012 = -0.014*p_{d}\\p_{d}=\frac{-0.012}{-0.014}=0.857\\\\p_{bp}=1-p_{d}=1-0.857=0.143$

(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.

It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.

The water removed of every 100 kg of dry air is

$100 kgDA*0.857*0.014 kgW/kgDA= 1.1998 \approx 1.2 kgW$

It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).

100 * 0.012 = 1.2 kgW

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3 years ago

If an element has two isotopes, what is the atomic mass if one of the isotopes has a mass of 15.000 amu and makes up 5.000% of t

olasank [31]

The atomic mass of element is the weighted average atomic mass of the element with respect to the abundance of the isotopes of that element
atomic mass is the sum of the products of the mass of isotopes by their percentage abundance
atomic mass = 15.000 amu x 5.000 % + 16.000 amu x 95.000 %
= 0.7500 + 15.200
atomic mass of element is therefore 15.950

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3 years ago

What is the temperature change in 355 mL of water upon absorption of 34 kJ of heat? (The specific heat capacity of water is 4.18

frozen [14]

The temperature change is 23 °C.

q = mCΔT

ΔT = q/(mC)

m = 355 g

∴ ΔT = (34 000 J)/(355 g × 4.184 J·°C⁻¹g⁻¹) = 23 °C

Note: The answer can have only two significant figures because that is all you gave for the amount of heat absorbed.

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3 years ago

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