Answer: The gravitational acceleration on planet X is 5 N/kg
On Earth (with the gravitational accelartion g_E) the mass of 2kg will correspond to

On planet X we are told the same measure is only 10N. Since there is a proportional relationship between g and F, we can calculate g_X:

The impulse J is equal to the magnitude of the force applied to the cannonball times the time it is applied:

But the impulse is also equal to the change in momentum of the cannonball:

If we put the two equations together, we find

And since we know the magnitude of the average force and the time, we can calculate the change in momentum:
Answer: #1. Close the door when air conditioner is on #2. I would use only 1 paper towel when drying your hands #3. Recycle #4. use water bottles that are not to be plastic.
<em>So these are things that you can do to conserve the resources from the environment in your school! </em> So hopefully i had helped you answer this question! Have a Great Day!
Answer:
dt/dx = -0.373702
dt/dy = -1.121107
Explanation:
Given data
T(x, y) = 54/(7 + x² + y²)
to find out
rate of change of temperature with respect to distance
solution
we know function
T(x, y) = 54 /( 7 + x² + y²)
so derivative it x and y direction i.e
dt/dx = -54× 2x / (7 +x² + y²)² .........................1
dt/dy = -54× 2y / (7 + x² + y²)² .........................2
now put the value point (1,3) as x = 1 and y = 3 in equation 1 and 2
dt/dx = -54× 2(1) / (7 +(1)² + (3)²)²
dt/dx = -0.373702
and
dt/dy = -54× 2(3) / (7 + (1)² + (3)²)²
dt/dy = -1.121107