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miskamm [114]
3 years ago
5

With what force will a car hit a tree if the car has a mass of 3,000 kg and it is accelerating at a rate of 2m/s2

Physics
1 answer:
Arisa [49]3 years ago
6 0
<span>F=ma = 3000x2m/sec^2 =6000 newtons. </span>
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A body of mass m moves along y such that at time t its position is y(t)= at^2 – bt + c, where a, b, c are constant.
Akimi4 [234]

Answer:

what do u need help with

Explanation:

A body of mass m moves along X-axis such that its position co-ordiante at any instant t is x = `at^(4)

3 0
3 years ago
How does a van de graff generator discharge
attashe74 [19]
<h3><u>Van de graff generator discharge:</u></h3>

A "Van de Graaff generator" is a device that has been designed to produce static electricity. The van de graff generator works on the principle of "electrostatic induction", due to which electrostatic potential is constant at any other point throughout the conductor.

It is also observed that van de graff discharge takes place in air or gases which are readily pointed at the conductors. Discharge occurs in the air because most of the static charges get removed by the gases present in the air.

7 0
3 years ago
Velocity differs from speed in that velocity indicates a particle's __________ of motion.
masha68 [24]
Velocity differs from speed in that velocity indicates a particle's <span>direction of motion. 

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5 0
3 years ago
Which of the following is NOT one of the three components of a nucleotide?
mart [117]
A. Carboxylate group
5 0
4 years ago
A.Whale communication. Blue whales apparently communicate with each other using sound of frequency 17.0 Hz, which can be heard n
Y_Kistochka [10]

A. 90.1 m

The wavelength of a wave is given by:

\lambda=\frac{v}{f}

where

v is the speed of the wave

f is its frequency

For the sound emitted by the whale, v = 1531 m/s and f = 17.0 Hz, so the wavelength is

\lambda=\frac{1531 m/s}{17.0 Hz}=90.1 m

B. 102 kHz

We can re-arrange the same equation used previously to solve for the frequency, f:

f=\frac{v}{\lambda}

where for the dolphin:

v = 1531 m/s is the wave speed

\lambda=1.50 cm=0.015 m is the wavelength

Substituting into the equation,

f=\frac{1531 m/s}{0.015 m}=1.02 \cdot 10^5 Hz=102 kHz

C. 13.6 m

Again, the wavelength is given by:

\lambda=\frac{v}{f}

where

v = 340 m/s is the speed of sound in air

f = 25.0 Hz is the frequency of the whistle

Substituting into the equation,

\lambda=\frac{340 m/s}{25.0 Hz}=13.6 m

D. 4.4-8.7 m

Using again the same formula, and using again the speed of sound in air (v=340 m/s), we have:

- Wavelength corresponding to the minimum frequency (f=39.0 Hz):

\lambda=\frac{340 m/s}{39.0 Hz}=8.7 m

- Wavelength corresponding to the maximum frequency (f=78.0 Hz):

\lambda=\frac{340 m/s}{78.0 Hz}=4.4 m

So the range of wavelength is 4.4-8.7 m.

E. 6.2 MHz

In order to have a sharp image, the wavelength of the ultrasound must be 1/4 of the size of the tumor, so

\lambda=\frac{1}{4}(1.00 mm)=0.25 mm=2.5\cdot 10^{-4} m

And since the speed of the sound wave is

v = 1550 m/s

The frequency will be

f=\frac{v}{\lambda}=\frac{1550 m/s}{2.5\cdot 10^{-4} m}=6.2\cdot 10^6 Hz=6.2 MHz

3 0
3 years ago
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