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Bond [772]
1 year ago
13

write name or formula of following coordination compounds. write oxidation state of metal ion in each compound. write electronic

configuration of each metal ion. 1. [v(oh2)6](no3)3 2. (nh4)2[cocl4] 3. [co(py)4]br2 4. k4[mn(cn)6] 5. [co(p(ch3)3)4]2(so4) 6. Ni(NH3)4Cl2 7. [CrCl2(OH2)4]+
Chemistry
1 answer:
Goshia [24]1 year ago
4 0

The coordination compounds' names or formulas, the oxidation state of each metal ion, and the electronic configuration of the each metal ion.

1. [V(OH2)6](NO3)3 - Vanadium(V) Oxidation State: +5 Electronic Configuration: [Ar] 3d3 4s2
2. (NH4)2[CoCl4] - Cobalt(II) Oxidation State: +2 Electronic Configuration: [Ar] 3d7 4s2
3. [Co(py)4]Br2 - Cobalt(III) Oxidation State: +3 Electronic Configuration: [Ar] 3d6 4s2
4. K4[Mn(CN)6] - Manganese(II) Oxidation State: +2 Electronic Configuration: [Ar] 3d5 4s2
5. [Co(P(CH3)3)4]2(SO4) - Cobalt(III) Oxidation State: +3 Electronic Configuration: [Ar] 3d6 4s2
6. Ni(NH3)4Cl2 - Nickel(II) Oxidation State: +2 Electronic Configuration: [Ar] 3d8 4s2
7. [CrCl2(OH2)4]+ - Chromium(III) Oxidation State: +3 Electronic Configuration: [Ar] 3d5 4s1

What is Electronic Configuration?
The arrangement of an atom's or molecule's (or other physical structure's) electrons in their atomic or molecular orbitals is known as the electron configuration in atomic physics as well as quantum chemistry. For instance, the neon atom's electron configuration is 1s2 2s2 2p6, which means that 1, 2 and 6 electrons, respectively, are present in each of the 1s, 2s, and 2p subshells. According to electronic configurations, each electron moves independently within an orbital while being surrounded by an average field produced by all other orbitals. Slater determinants as well as configuration state functions are used to mathematically describe configurations.

To learn more about Electronic Configuration
brainly.com/question/21977349
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The diatomic molecule of chlorine, cl2, is held together by a(n)____ covalent bond.
kvasek [131]

Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.

Covalent Bond :

It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .

Formation of covalent bond in Cl₂ :

Chlorine is present in group 17 in p block , It is a non metal .

The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .

Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .

From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .

Now the octet of both the atom are complete and they are in stable state together .

When both Cl atom share one e⁻ , there is a bond formed between Cl atoms . One bond consists of 2⁻ . Hence in Cl₂ SINGLE covalent bond present .

Cl + Cl -> Cl₂

7 0
4 years ago
Which statement describes both homogeneous mixtures and heterogeneous mixtures?
Lana71 [14]

C. Their components can be separated by physical processes.

6 0
4 years ago
Read 2 more answers
(a) Write the reaction for the overall oxidation of propane (C3H8) with oxygen to produce CO2 and water.
Pavlova-9 [17]

Answer:

Oxidation is the loss of electrons, that is, addition of electronegetive elements, example is addition of oxygen. Also, removal of electropositive elements, example is removal of hydrogen.

Explanation: a) In the presence of excess oxygen, propane burns in air, which gives the following chemical equation:

C3H8 + 5O2⇒ 3CO2 + 4H2O +Heat

b) When insufficient oxygen or too much oxygen is present for complete combustion, the following equation is given:

2C3H8 + 9O2 ⇒ 4CO2 + 2CO + 8H2O + Heat

c) At the anode( negative terminal): O∧2- ⇒ O + e

Oxygen accepts electron.

d) At cathode ( positive terminal): H∧+ + e∧- ⇒ H

Hydrogen donates electron

d) Nernst equation for reversal potential is given as follows:

E= RT/zF  In{ion outside cell}/{ion inside cell}= 2.303 RT/zF In{ion outside cell}/{ion inside cell}

4 0
4 years ago
Can someone help me I need help please!
zavuch27 [327]

Answer:

Explanation:

the number above the letter is the atomic number and the other on the bottom is the atomic mass . and the mass number is the atomic mass . and protons is the number above the letter along with neutrons electrons you just do atomic mass - atomic number = electrons

example 1 -2= 1 so there is the atomic number of 1 and atomic mass of 2

let me know if this helps

6 0
3 years ago
The laws of nature:
GenaCL600 [577]

Answer:

B

Explanation:

they actually say the same thing they differ with smaller things

4 0
2 years ago
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