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2 years ago

Identify the correct equilibrium constant expression for this equation:

Chemistry

2 answers:

Nat2105 [25]2 years ago

7 0

Answer:

For the first one it is B

For the second one it is C

Explanation:

yourwelcome

mina [271]2 years ago

3 0

Answer:

First Option: B)

Second Option: C)

The pictures below will show the answers. The first picture is the first option, and the second picture is the second option.

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Calculate the energy, in joules, required to ionize a hydrogen atom when its electron is initially in the n =2 energy level. The

qaws [65]

Answer:

$E_{ionization}=5.45\times 10^{-19}\ J$

Explanation:

$E_n=-2.18\times 10^{-18}\times \frac{1}{n^2}\ Joules$

For transitions:

$Energy\ Difference,\ \Delta E= E_f-E_i =-2.18\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J$

So, $n_i=2$ and $n_f=\infty$ (As the hydrogen has to ionize)

Thus,

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J$

$\Delta E=2.18\times 10^{-18}(\frac{1}{2^2})\ J$

$E_{ionization}=5.45\times 10^{-19}\ J$

4 0

3 years ago

Please help I really appreciate it thank you ❤️

Feliz [49]

II. sulfur (S) and carbon (C)

and

III. fluorine (F) and oxygen (O)

will form covalent bonds, so the answer will be:

e. II and III

Explanation:

To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.

If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.

If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)

If the electronegativity difference is greater then 1.8 there is an ionic bond.

We have the following cases:

I. lithium (Li) and sulfur (S)

electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic

II. sulfur (S) and carbon (C)

electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent

III. fluorine (F) and oxygen (O)

electronegativity difference = 4 (F) - 3.5 (O) = 0.5 so the bond will be polar covalent bond.

Learn more about:

covalent and ionic bonds

brainly.com/question/1802971

#learnwithBrainly

3 0

3 years ago

g For the following reaction, 0.500 moles of silver nitrate are mixed with 0.285 moles of copper(II) chloride. What is the formu

scZoUnD [109]

Answer:

$CuCl_2$ is the formula for the limiting reagent.

Mass of silver chloride produced is 71.8 g.

Explanation:

$CuCl_2+2AgNO_3\rightarrow 2AgCl+Cu(NO_3)_2$

Moles of silver nitrate = 0.500 mol

Moles of copper(II) chloride = 0.285 mol

According to reaction, 2 moles of silver nitrate reacts with 1 mole of copper chloride , then 0.500 mole of silver nitrate will react with :

$\frac{1}{2}\times 0.500 mol=0.250 mol$ of copper(II) chloride

As we can see that moles of copper(II) chloride will be reacting is 0.250 mol less than present moles of copper (II) chloride ,so this means that silver nitrate is limiting reagent.

And moles of silver chloride to be formed will depend upon silver nitrate.

According to reaction, 2 moles of silver nitrate gives 2 moles of silver chloride , then 0.500 mole of silver nitrate will give :

$\frac{2}{2}\times 0.500 mol=0.500 mol$ of silver chloride

Mass of silver chloride produced:

0.500 mol × 143.5 g/mol = 71.8 g

7 0

3 years ago

3 Apply Many scientific words, such as matter, also have everyday meanings. Use context clues to write your own definition for e

rodikova [14]

Answer:

Explanation:

Use context clues to write your own definition for each meaning of the word matter.

Example sentence

What is this gooey matter on the table?

Matter:

__________

Example sentence

Please vote! Your opinions matter.

Matter:

__________

3 0

1 year ago

The Hall process for the production of aluminum involves the reaction of aluminum oxide with elemental carbon to give aluminum m

topjm [15]

Answer:

1.7 × 10³ kg of ore.

Explanation:

Call X the amount of aluminum ore mined to produce 1.0 × 10³ kg the aluminum metal.

Then, taking into account the yield of the reaction (82 % = 0.82) and the percent of aluminun in the ore (71% = 0.71), you can write the following equation:

X × 71% × 82% = 1.0 × 10³ kg

↑ ↑ ↑ ↑

(mass of ore) (% of Al in the ore) (yield) ( Al metal to obtain)

You must just simplify, solve and compute:

0.71 × 0.82 × X = 1,000

X = 1,000 / (0.71 × 0.82) = 1,000 / 0.5822 = 1,717.6 Kg

Round to two significant figures; 1,700 kg = 1.7 × 10³ kg of ore ← answer.

6 0

3 years ago

Read 2 more answers