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Ivan
3 years ago
8

HELP ASAP!!!

Chemistry
1 answer:
Eva8 [605]3 years ago
3 0
Producing energy is the answer
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3CuCl2 + 2Al => 3Cu + 2AlCl3
Marrrta [24]

The reaction includes the single replacement reaction and redox

<h3>Further explanation</h3>

Single replacement : one element replaces another element in a compound

A + BC ⇒ AC + B

The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number

3CuCl + 2Al => 3Cu + 2AlCl₃

  • 1. Single replacement

Al replacing Cu in the CuCl compound

  • 2. Redox reaction

3Cu²⁺ + 6e⁻⇒ 3Cu reduction(oxidation number from +2 to 0)

2Al⇒2Al³⁺+6e⁻ oxidation(oxidation number from 0 to +3)

8 0
3 years ago
If you have 5 unknowns and they were secondary alcohol aldehyde, carboxylic acid, amine, and alkane Put plan to identify the unk
Finger [1]

Answer:

the unknowns

Explanation:

7 0
3 years ago
The eagle has landed was said when man landed on mars or on the moon
nekit [7.7K]
The moon, man has not been to mars yet
7 0
3 years ago
An atom that has a negative four charge will have one of the following?
expeople1 [14]
B. An equal amount of protons and electrons
8 0
4 years ago
Read 2 more answers
At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
Aleks [24]

Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

We know, K_{p}=K_{c}(RT)^{\Delta n}

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and \Delta n is difference in sum of stoichiometric coefficient of products and reactants

Here \Delta n=(2)-(2+1)=-1 and T = 311 K

So, K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}

Hence value of equilibrium constant in terms of partial pressure (K_{p}) is 4.35\times 10^{-4}

4 0
3 years ago
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