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3 years ago

When an atom of n-14 is bombarded by an alpha particle, the single product is?

Chemistry

2 answers:

riadik2000 [5.3K]3 years ago

5 0

Answer: The correct answer is Option c.

Explanation:

Alpha particle is released when an atom undergoes alpha decay. This particle carries a charge of +2 units and has a mass of 4 units. This is also considered as a helium nucleus.

In the question:

An atom of N-14 is bombarded with alpha particle, so the equation for this reaction follows:

$_7^{14}\textrm{N}+_2^4\alpha \rightarrow _9^{18}\textrm{F}$

Hence, the correct answer is Option c.

aliya0001 [1]3 years ago

4 0

For the answer to the question above asking when an atom of n-14 is bombarded by an alpha particle, the single product is?

 You're starting with 14/7 N, correct?

An alpha particle is two protons, two neutrons, which is 4/2, correct?
So I think the answer to your question is the third one which is c. 18/9 f

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A chemical compound that contains the –NH2 functional group is a(n) _____.

kirill115 [55]

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3 years ago

Based on the kinetic theory, which statement is true? (5 points)

Hoochie [10]

Answer:

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Explanation:

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2 years ago

How many moles are in 35.0 grams of H₂O?

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1.94 moles

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3 years ago

One isotope of oxygen differs from another isotope of oxygen in *

Reptile [31]

Each isotope of Oxygen has a different number of neutrons

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Atomic mass is the average atomic mass of all its isotopes

Isotopes are atoms has the same number of protons but has a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Some of the isotopes of oxygen are:

$\tt _8^{16}O,_8^{17}O,_8^{18}O$

Each isotope has 8 protons and 8 electrons but has a different number of neutrons

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2 years ago

Write Lewis structures for the following molecules: (a) ICl, (b) PH3, (c) P4 (each P is bonded to three other P atoms), (d) H2S,

spin [16.1K]

Answer : The Lewis-dot structure for the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

Now we have to determine the Lewis-dot structure for the following molecules.

(a) The given molecule is, $ICl$

As we know that iodine and chlorine have '7' valence electrons.

Therefore, the total number of valence electrons in $ICl$ = 7 + 7 = 14

According to Lewis-dot structure, there are 2 number of bonding electrons and 12 number of non-bonding electrons.

(b) The given molecule is, $PH_3$

As we know that phosphorous has '5' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in $PH_3$ = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(c) The given molecule is, $P_4$

As we know that phosphorous has '5' valence electrons.

Therefore, the total number of valence electrons in $P_4$ = 4(5) = 20

According to Lewis-dot structure, there are 6 number of bonding electrons and 14 number of non-bonding electrons.

(d) The given molecule is, $H_2S$

As we know that sulfur has '6' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in $H_2S$ = 6 + 2(1) = 8

According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.

(e) The given molecule is, $N_2H_4$

As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in $N_2H_4$ = 2(5) + 4(1) = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(f) The given molecule is, $HClO_3$

As we know that chlorine has '7' valence electrons, oxygen has '6' valence electrons and hydrogen has '1' valence electrons.

Therefore, the total number of valence electrons in $HClO_3$ = 1 + 7 + 3(6) = 26

According to Lewis-dot structure, there are 12 number of bonding electrons and 14 number of non-bonding electrons.

(g) The given molecule is, $COBr_2$

As we know that bromine has '7' valence electrons, oxygen has '6' valence electrons and carbon has '4' valence electrons.

Therefore, the total number of valence electrons in $COBr_2$ = 4 + 6 + 2(7) = 24

According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.

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2 years ago