Question

When an atom of n-14 is bombarded by an alpha particle, the single product is?

Answer 1

Answer: The correct answer is Option c.

Explanation:

Alpha particle is released when an atom undergoes alpha decay. This particle carries a charge of +2 units and has a mass of 4 units. This is also considered as a helium nucleus.

In the question:

An atom of N-14 is bombarded with alpha particle, so the equation for this reaction follows:

$_7^{14}\textrm{N}+_2^4\alpha \rightarrow _9^{18}\textrm{F}$

Hence, the correct answer is Option c.

Answer 2

For the answer to the question above asking when an atom of n-14 is bombarded by an alpha particle, the single product is?

 You're starting with 14/7 N, correct? 

An alpha particle is two protons, two neutrons, which is 4/2, correct? 
So I think the answer to your question is the third one which is c. 18/9 f