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1 year ago

Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy?

1 answer:

4 0

Jemima is running with a velocity of 5m/s. She has a mass of 65kg, what is her kinetic energy would be 812.5 Joules.

<h3>What is mechanical energy?</h3>

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

As given in the problem we have to calculate the Kinetic energy of the Jemima,

Kinetic energy = 1/2 ×mass×velocity²

=0.5×65×5²

=812.5 Joules

Thus, the kinetic energy of the Jemima would be 812.5 Joules.

To learn more about mechanical energy, refer to the link;

brainly.com/question/12319302

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F=G=50 N

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A 25 kg block is held against a compressed spring and then the spring is allowed to decompress giving the block a velocity. The

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Answer:

h=18.05 cm

Explanation:

Given that

m= 25 kg

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From energy conservation

$\dfrac{1}{2}Kx^2=\dfrac{1}{2}mv^2$

$Kx^2=mv^2$

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When block reach at the maximum height(h) position then the final speed of the block will be zero.

We know that

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By putting the values

$0^2=1.9^2-2\times 10\times h$

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h=18.05 cm

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4 years ago

When you throw a ball upward, its kinetic energy and its potential energy . When the ball reaches maximum height, its kinetic en

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It has zero kinetic energy, more potential energy

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Read 2 more answers

During takeoff, an airplane climbs with a speed of 195 m/s at an angle of 15° above the horizontal. The speed and angle constitu

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Answer:

The horizontal component of the velocity is 188 m/s

The vertical component of the velocity is 50 m/s.

Explanation:

Hi there!

Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:

We can find vx using the following trigonometric rule of a right triangle:

cos α = adjacent / hypotenuse

cos 15° = vx / 195 m/s

195 m/s · cos 15° = vx

vx = 188 m/s

The horizontal component of the velocity is 188 m/s

To calculate the y-component we will use the following trigonometric rule:

sin α = opposite / hypotenuse

sin 15° = vy / 195 m/s

195 m/s · sin 15° = vy

vy = 50 m/s

The vertical component of the velocity is 50 m/s.

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3 years ago

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Answer:

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