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4 years ago

6

A brick moves across a rough surface at constant velocity. Which of the following are forces that should be included in a free b

ody diagram?

1 answer:

12345 [234]4 years ago

3 0

But friction is what would make it slow down so...

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A flagpole consists of a flexible, 7.107.10 m tall fiberglass pole planted in concrete. The bottom end of the flagpole is fixed

vladimir1956 [14]

To develop this problem we require the concepts related to Frequency and their respective way of calculating it.

The formula to calculate the frequency is given by

$f=\frac{V}{\lambda}$

Where,

$\lambda = wavelength$

$V= velocity$

For fundamental mode, wavelength is equal to 4 time the length.

Then,

$\lambda = 4L = 4*7.10m=28.4m$

Replacing in the first equation,

$f=\frac{2730}{28.4}\\$

$f= 96.12Hz$

Therefore the frequency is 96.12Hz

3 0

3 years ago

Starting over, so here's some points! Take em<br> ~Jayden

Serhud [2]

Answer:

Thank you again!!!! :D

8 0

3 years ago

Read 2 more answers

PHYSICS HELP PLEASE! will vote brainliest if valid answer! and 20pts!

7nadin3 [17]

The force that pulls the wagon is the horizontal component of the actual force, which is 290*cos(32) = 246N

4 0

3 years ago

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There are Z protons in the nucleus of an atom, where Z is the atomic number of the element. An α particle carries a charge of +2

qaws [65]

Answer:

$r = 2.84 \times 10^{-14} m$

Explanation:

As per energy conservation we know that the electrostatic potential energy of the charge system is equal to the initial kinetic energy of the alpha particle

So here we can write it as

$\frac{1}{2}mv^2 = \frac{k(2e)(ze)}{r}$

now we know that

$m = 1.67 \times 10^{-27} kg$

$e = 1.6 \times 10^{-19} C$

z = 79

here kinetic energy of the incident alpha particle is given as

$KE = 6.4 \times 10^{-13} J$

now we have

$6.4 \times 10^{-13} = \frac{(9\times 10^9)(1.6 \times 10^{-19})^2(79)}{r}$

now we have

$r = 2.84 \times 10^{-14} m$

7 0

3 years ago

why is a train more difficult to stop then a rolling ball even if they are traveling at the same speed? URGENT

zloy xaker [14]

Think of the formula force=mass x acceleration. even though they have the same acceleration, a train has more mass. is that helpful?

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3 years ago