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Semenov [28]
3 years ago
12

An oscillator creates periodic waves on two strings made ofthe same material. The tension is the same in both strings.If the str

ings have different thicknesses,which of the following parameters, if any, will be different in thetwo strings?Check all that apply.a. wave frequencyb. wave speedc. wavelengthd. none of the above
Physics
1 answer:
Novay_Z [31]3 years ago
7 0

Answer:

c. wavelength

Explanation:

The speed of the wave on the string is given by

v= \sqrt{\frac{T}{\mu} }

Here, \mu is the mass per unit length and T is the tension in the string.

For the different thickness, the mass per unit length is different. Therefore, the wave speed is different in the two strings.

The frequency of the oscillations depends upon the oscillator. So, the frequency is same for the two strings by using same oscillator.

The frequency and speed relation is,

f= γλ

λ= f/γ

Since frequency is constant, the wavelength of the waves different as the speeds are different.

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Given the equation E = P/N , solve for P
Mars2501 [29]

Answer:

E=P/N

multiply both sides by N

P=EN

6 0
3 years ago
Compute the kinetic energy of a proton (mass 1.67×10−27kg ) using both the nonrelativistic and relativistic expressions for spee
JulsSmile [24]

Answer:

The non-relativistic kinetic energy of a proton is 6.76\times10^{-12}\ J

The relativistic kinetic energy of a proton is 7.25\times10^{-12}\ m/s

Explanation:

Given that,

Mass of proton m=1.67\times10^{-27}\ kg

Speed v= 9.00\times10^{7}\ m/s

We need to calculate the kinetic energy for non relativistic

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

Put the value into the formula

K.E=\dfrac{1}{2}\times1.67\times10^{-27}\times(9.00\times10^{7})^2

K.E=6.76\times10^{-12}\ J

We need to calculate the kinetic energy for relativistic

Using formula of kinetic energy

K.E=mc^2(\sqrt{(\dfrac{1}{1-\dfrac{v^2}{c^2}})}-1)

K.E=1.67\times10^{-27}\times(3\times10^{8})^{2}\cdot\left(\sqrt{\frac{1}{1-\frac{\left(9.00\times10^{7}\right)^{2}}{(3\times10^{8})^{2}}}}-1\right)

K.E=7.25\times10^{-12}\ m/s

Hence, The non-relativistic kinetic energy of a proton is 6.76\times10^{-12}\ J

The relativistic kinetic energy of a proton is 7.25\times10^{-12}\ m/s

7 0
3 years ago
The phases of the moon occur because the moon revolves around the earth.<br><br> True<br><br> False
Ira Lisetskai [31]

Answer: True

Explanation:
The phases occur because the sun lights different parts of the moon as the moon revolves around the earth
7 0
3 years ago
Based on the principles of convection, conduction and thermal radiation, which scenario below is most similar to the following s
Ksivusya [100]

The situation (heat going through the ceiling) describes
conduction ...
heat going from one place to another by
soaking through some material.

A).  This is the one.  Heat goes from from the marshmallow
to your hand by soaking through the wire.   This is conduction too.

B).  No.  The heat in the room goes from the floor to the ceiling
because the warm air rises and carries it there.  This is convection.

C).  No.  There's nothing for the heat to soak through between
the sun and the roof, and nothing that can move from the sun
to the roof and bring the heat with it.  This is radiation.

D).  No.  Cold water sinks from the surface to the bottom because
warm water rose from the bottom to the surface, taking heat with it. 
This is convection.

5 0
3 years ago
Read 2 more answers
A particle (charge = +0.8 mC) moving in a region where only electric forces act on it has a kinetic energy of 6.7 J at point A.
Maksim231197 [3]

Answer:

The kinetic energy of the particle as it moves through point B is 7.9 J.

Explanation:

The kinetic energy of the particle is:

\Delta K = \Delta E_{p} = q\Delta V

<u>Where</u>:

K: is the kinetic energy

E_{p}: is the potential energy

q: is the particle's charge = 0.8 mC

ΔV: is the electric potential = 1.5 kV                                    

\Delta K = q \Delta V= 0.8 \cdot 10^{-3} C*1.5 \cdot 10^{3} V = 1.2 J

Now, the kinetic energy of the particle as it moves through point B is:

\Delta K = K_{f} - K_{i}

K_{f} = \Delta K + K_{i} = 1.2 J + 6.7 J = 7.9 J

Therefore, the kinetic energy of the particle as it moves through point B is 7.9 J.

I hope it helps you!      

8 0
3 years ago
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