<span>Changes that occur during metamorphism ... The metamorphic rock shale normally becomes following low grade metamorphism.</span>
Answer:
The correct answer is "Evaporation of water from the soil will increase".
Explanation:
Evaporation is the step of the hydrologic cycle at which deposits of liquid water got into the atmosphere by transforming into a water vapor. The level of evaporation is closely related with the surface area of foliage, where the more surface area of foliage the less evaporation will occur. Therefore, if large areas of land experience clear-cutting, evaporation of water from the soil will increase.
Vertically we can say
<span>Vertical acceleration = - g </span>
<span>Vertical velocity = u sinѲ - gt [Ѳ = 42; u = 12 m/s] </span>
<span>Vertical displacement = u sinѲt - (1/2) g t^2 + 9.5 </span>
<span>When the rock hits the ground, its vertical displacement will be zero. So we can say.. </span>
<span>u sinѲt - (1/2) g t^2 + 9.5 = 0 </span>
<span>I'll rearrange this .... </span>
<span>- (1/2) g t^2 + u sinѲt + 9.5 = 0 </span>
<span>Can you see that we now have a quadratic in t? </span>
<span>Using the well known formula </span>
<span>t = [ - u sinѲ ± √( u^2 sin^2Ѳ - 4(( - (1/2)g * 9.5))] / (- g) </span>
<span>t = [- u sinѲ ± √( u^2 sin^2Ѳ + 19g)] / (-g) </span>
<span>t = [- 8.03 ± √(250.86)] / (-9.81) </span>
<span>t = [- 8.03 ± 15.84] / (-9.81) </span>
<span>t = (- 8.03 + 15.84) / (-9.81) or t = (-8.03 - 15.84) / (-9.81) </span>
<span>t = - 0.8 or t = 2.43 </span>
<span>Well, a negative time has no meaning so </span>
<span>t = 2.43 seconds. </span>