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2 years ago

A transformer has an input of 24 V and an output of 36 V. If the input is changed to 12 V what will the output be?

Physics

1 answer:

mote1985 [20]2 years ago

4 0

ANSWER:

18 V

STEP-BY-STEP EXPLANATION:

Given:

Initial condition (1):

input voltage = Vi1 = 24 V

output voltage = Vo1 = 36 V

Final condition (2):

input voltage = Vi2 = 12 V

We can calculate the output voltage of the final condition as follows:

$\begin{gathered} \frac{V_{i1}}{V_{o1}}=\frac{V_{\imaginaryI2}}{V_{o2}} \\ \\ \text{ We replacing:} \\ \\ \frac{24}{36}=\frac{12}{V_{o2}} \\ \\ V_{o2}=\frac{12}{24}\cdot36 \\ \\ V_{o2}=18\text{ V} \end{gathered}$

Therefore, in the final condition, the output voltage will be 18 volts.

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Noble Gases do not readily form compounds because they ___ chemically stable with 8 valence electrons

azamat

Answer : Noble Gases do not readily form compounds because they are chemically stable with 8 valence electrons.

Explanation :

Noble gases are the chemical elements that are present in group 18 in the periodic table.

The elements are helium, neon, argon, krypton, xenon and radon.

They are chemically most stable except helium due to having the maximum number of 8 valence electrons can hold their outermost shell that means they have a complete octet.

They are rarely reacts with other elements to form compounds by gaining or losing electrons since they are already chemically stable.

Hence, the noble Gases do not readily form compounds because they are chemically stable with 8 valence electrons.

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3 years ago

What elements are good conductors of electricity?

kramer

In solids: All metals are good conductors of electricity as they contain free moving electrons. Non-metals doesn't conduct , but we consider Graphite the only non-metal that can conduct electricity for the presence of free moving electrons.

In Liquids ; Ionic compunds contains free moving ions , so they conduct electricity as well .

6 0

4 years ago

What is v^2=0.05-4.9 please i need this asap

Margaret [11]

Answer:

v =2.02

Explanation:

v^2=0.05-4.9

v^2=-4.85

square root both side

v=2.02

^^^^this is a not a perfect square

7 0

3 years ago

The following time dependent force is applied to a 2 kg block that is initially at rest on a frictionless and horizontal surface

DerKrebs [107]

Answer:

The displacement of the block is 9 m.

Explanation:

Given that,

Mass of block = 2 kg

Time = 3 sec

The force is

$F(t)=4t$

The acceleration is

$a=\dfrac{F}{m}$

Put the value into the formula

$a=\dfrac{4t}{2}$

$a=2t$

We need to calculate the velocity

Using formula of acceleration

$v=\int_{0}^{t}{a dt}$

Put the value into the formula

$v=\int_{0}^{3}(2t dt)$

$v=(\dfrac{2t^2}{2})_{0}^{3}$

$v=(t^2)_{0}^{3}$

$v=9\ m/s$

We need to calculate the displacement

Using formula of velocity

$s=\int_{0}^{3}(v dt)$

$s=(t^2)_{0}^{3}$

$s=(\dfrac{t^3}{3})_{0}^{3}$

$s=9\ m/s$

Hence, The displacement of the block is 9 m.

8 0

3 years ago

Read 2 more answers

Suppose that a parallel-plate capacitor has circular plates with radius R = 25 mm and a plate separation of 4.7 mm. Suppose also

ozzi

Answer:

a) $B_{max} = 1.784*10^{-12}$

Explanation:

Given paraeters are:

R = 25 cm

d = 4.7 mm

f = 60 Hz

$V_m$ = 160 V

a) $V = V_msin(2\pi ft)$

Where $f = 60$ Hz and $V_m = 160$ V

$E =V/d= \frac{V_msin(2\pi ft)}{d}$

For $r = R$

$A = \pi R^2$

Since $\Phi_E = EA$

$\Phi_E=\frac{\pi R^2V_msin(2\pi ft) }{d}$

From Ampere's Law:

$\int B.ds = \mu_0\epsilon_0\frac{d\Phi_E}{dt} + \mu_0I_{encl}$ where $I_{encl}=0$

So at $r = R$ ,

$B.2\pi R = \mu_0\epsilon_0\frac{d\Phi_E}{dt}\\B.2\pi R = \mu_0\epsilon_0\frac{2\pi^2fR^2V_mcos(2\pi ft)}{d}\\B = \frac{\mu_0\epsilon_0\pi fRV_mcos(2\pi ft)}{d}$

For maximum B, cos(2πft) = 1. Hence,

$B_{max}=\frac{\mu_0\epsilon_0\pi fRV_m}{d}=\frac{4\pi*10^{-7}*8.85*10^{-12}*\pi*60*0.025*160}{4.7*10^{-3}}=1.784*10^{-12}$ T

b) From r = 0 to r = R = 0.025 m, by Ampere's Law, the equation will be:

$B = \frac{\mu_0\epsilon_0\pi fR^2V_m}{rd}$

From r = R = 0.025 m to r = 0.1 m, by Ampere's Law, the equation will be:

$B = \frac{\mu_0\epsilon_0\pi fRV_m}{d}$

The plot is given in the attachment.

5 0

4 years ago