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1 year ago

What is the molarity of a solution that was prepared by dissolving 82 g of cacl2?

Chemistry

1 answer:

ExtremeBDS [4]1 year ago

7 0

The molarity of a solution is 0.909 M.

m(CaCl₂) = 82 g; mass of calcium chloride

M(CaCl₂) = 111 g/mol; molar mass of calcium chloride

n(CaCl₂) = m(CaCl₂) ÷ M(CaCl₂)

n(CaCl₂) = 82 g ÷ 111 g/mol

n(CaCl₂) = 0.74 mol; amount of calcium chloride

V(CaCl₂) = 812 mL = 0.812 L; volume of calcium chloride

c(CaCl₂) = n(CaCl₂) ÷ V(CaCl₂)

c(CaCl₂) = 0.74 mol ÷ 0.812 L

c(CaCl₂) = 0.909 mol/L = 0.909 M; molarity of calcium chloride

Calcium chloride is a inorganic salt with ionic bonds between calcium and chlorine. It is a colorless crystalline solid at room temperature, highly soluble in water.

More about molarity: brainly.com/question/26873446

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2 years ago

A 1.00 liter container holds a mixture of 0.52 mg of He and 2.05 mg of Ne at 25oC. Determine the partial pressures of He and Ne

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Answer:

pHe = 3.2 × 10⁻³ atm

pNe = 2.5 × 10⁻³ atm

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Explanation:

Given data

Volume = 1.00 L

Temperature = 25°C + 273 = 298 K

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mNe = 2.05 mg = 2.05 × 10⁻³ g

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0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol

We can find the partial pressure of He using the ideal gas equation.

P × V = n × R × T

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P = 3.2 × 10⁻³ atm

The molar mass of Ne is 20.18 g/mol. The moles of Ne are:

2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol

We can find the partial pressure of Ne using the ideal gas equation.

P × V = n × R × T

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3 years ago

1 lb of CO2 occupies 0.6 ft^3 at a pressure of 200 psi. Determine the temperature of the system.

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<u>Answer:</u> The temperature of the system is 273 K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of carbon dioxide = 1 lb = 453.6 g (Conversion factor: 1 lb = 453.6 g)

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

$\text{Moles of carbon dioxide}=\frac{453.6g}{44g/mol}=10.31mol$

To calculate the temperature of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide = 200 psia = 13.6 atm (Conversion factor: 1 psia = 0.068 atm)

V = Volume of carbon dioxide = $0.6ft^3=16.992L$ (Conversion factor: $1ft^3=28.32L$ )

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T = temperature of the system = ?

Putting values in above equation, we get:

$13.6atm\times 16.992L=10.31mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=273K$

Hence, the temperature of the system is 273 K

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