Respuesta:
292 g / mol;
Por favor, consulte la explicación.
Explicación:
El número de átomos de cada elemento en el compuesto: Fe2 (co3) 3.
Fe = 2; C = 3; 0 = 3 * 3 = 9
Fe2 = 112 g / mol
C = 12 g / mol
O = 16 g /
Masa molecular = ((112 + (12 * 3) + (16 * 9)
= (112 + 36 + 144)
= 292 g / mol.
Total = 2 + 3 + 9 = 14
Fe2 = 112/292 * 100% = 38,356%
C = 36/292 * 100% = 12,328 * '
O = (16 * 9) / 292 * 100% = 49,32%
It's adenosine triphosphate !
it has Penrose sugar and phosphate as backbone !
and nitrogenous base ... adenine.... in the middle !
In chemical reactions, the actual yield is not the same as the expected yield . Actual yield is lower than the theoretical yield . Then we have to find the yield percentage. To see what percentage of the theoretical yield is the actual yield.
Percent yield = actual yield / theoretical yield x 100%
Percent yield = 24.6/55.9 x100%
Percent yield = 44%
Mass = mr x moles
Mr of CuCl2 = ( 63.5) + ( 35.5 x 2) = 134.5
2.5 = 134.5 x moles
2.5 / 134.5 = moles
Moles = 0.019 (2DP)
0.25g of Al
Mr of Al = 27
0.25 = 27 x moles
0.25/ 27 = 0.0093 moles (2sf)
Hope this helps :)
Answer:
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