What are the products for the following equation?<br><br>NaCl + H2O ->

The atomic mass of Gallium is 69.72 AMU. The masses of the naturally occurring isotopes are 68.9257 AMU and 70.908 AMU for Ga-69

Mashcka [7]

Answer:

40.7% abundance of Ga-71

59.93% abundance of Ga-69

Explanation:

Given data:

Average atomic mass of Ga = 69.72 amu

Atomic mass of Ga-69 = 68.9257 amu

Atomic mass of Ga-71 = 70.908 amu

Percent abundance of each isotope = ?

Solution;

we know there are two naturally occurring isotopes of Ga.

First of all we will set the fraction for both isotopes

X for the isotopes having mass 68.9257

1-x for isotopes having mass 70.908

we will use the following equation,

68.9257x + 70.908 (1-x) = 69.72

68.9257x +70.908 - 70.908x = 69.72

68.9257x - 70.908x = 69.72 - 70.908

-1.9823x = - 1.188

x= 1.188/1.9823

x= 0.5993

0.5993 × 100 = 59.93 %

59.93 % is abundance of Ga-69 because we solve the fraction x.

now we will calculate the abundance of Ga-71.

(1-x)

1 - 0.5993 = 0.4007

0.4007× 100= 40.7 %

40.7 % for Ga-71.

3 0

3 years ago

How to separate unreacted iron

taurus [48]

Answer:

through magnetization

6 0

3 years ago

A 0.8115 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL

inysia [295]

Answer:

Molarity of NaOH solution is 1.009 M

Explanation:

Molar mass of HCl is 36.46 g/mol

Number moles = (mass)/(molar mass)

So, 0.8115 g of HCl = $\frac{0.8115}{36.46}moles$ HCl = 0.02226 moles HCl

1 mol of NaOH neutralizes 1 mol of HCl.

So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is $\frac{S\times 22.07}{1000}moles$

So, $\frac{S\times 22.07}{1000}=0.02226$

or, S = 1.009

So, molarity of NaOH solution is 1.009 M

5 0

3 years ago

This chemical equation represents the burning of methane, but the equation is incomplete. What is the missing coefficient in bot

Zolol [24]

CH4+(x)O2=CO2 +(Y)H2O
C=1 +H=4 +O=? = C=1 +O=2+? +H=?
H=4>>Y=2
C=1 +H=4 +O=? = C=1 +O=(2+2) +H=4
C=1 +H=4 +O=4 = C=1 +O=4 +H=4
O=4>>X=2
CH4+(2)O2 =CO2 +(2)H2O

6 0

3 years ago

Read 2 more answers

How can you determine the specific heat of a metal using a calorimeter

zhannawk [14.2K]

Answer:

One can determine the specific heat of the metal through using the clarimeter, water, thermometer and using heat equations.

Explanation:

You can learn about heat effects and calorimetery through a simple experiment by boiling water and heating up the metal in it. Then, pour it into your calorimeter and the heat will flow from the metal to the water. The two equlibria will meet: the metal will loose heat into its surroundings (the water) and teh water will absorb the heat. The heat flow for the water is the same as it is for the metal, the only difference being is the negative sign indicating the loss of the heat of the metal.

In terms of theromdynamics, we can deteremine the heat flow for the metal becasue it would be equal to the mangnitued but opposite in direction. Thus, we can say that the specific heat of water qH2O = -qmetal.

4 0

3 years ago

What are the products for the following equation?NaCl + H2O ->​

What are the products for the following equation?NaCl + H2O ->