Based on a kc value of 0.200 and the given data table, what are the equilibrium concentrations of xy, x, and y, respectively?
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Answer:
t (years)= (10log 20/log 1000) in base 10
Step-by-step explanation:
N = 5 × 10^0.3t
N = 100 branches
100 = 5 × 10^0.3t
100/5 = 10^0.3t
20 = 10^0.3t
Taking log of both sides
Log 20 base 10 = 0.3t
Log 20 base 10 = (3/10)t
Multiply both sides by 10
10log 20 base 10 = 3t
Recall, log 1000 base 10 = 3
10 Log 20 base 10 = (log 1000 base 10)×t
t = (10Log 20 base 10)/(log 1000 base 10)
t (years)= (10log 20/log 1000) in base 10
The number of years it will take for the tree to have 100branches is (10log 20/log 1000) in base 10
