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timofeeve [1]
2 years ago
11

Determine if the equations are parallel, perpendicular, or neither​ANSWER ALL!!!!!!

Mathematics
1 answer:
Jet001 [13]2 years ago
4 0
I can’t quite see the image, can you send another to help you better:)
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Find KL. Round to the nearest hundredth.<br> d<br> Sut of<br> .1.3<br> 48<br> L
VARVARA [1.3K]

Answer:

1.3

Step-by-step explanation:

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4 0
2 years ago
Which graph shows the solution to the following inequality. -5c+2&lt;27
bogdanovich [222]

Answer:

c > -5

Step-by-step explanation:

-5c + 2 < 27    

      - 2    - 2         Subtract 2 from both sides

-5c < 25               Divide both sides by -5 and flip the sign

c > -5

I graphed the inequality on the graph below.

If this answer is correct, please make me Brainliest!

8 0
3 years ago
Can someone answer this? Thanks :)
Maslowich

Answer:

15ft

Step-by-step explanation:

Draw out the picture and use the Pythagorean theorem (equation is written in blue) to solve.

View Image

4 0
2 years ago
50 points For these answers
Y_Kistochka [10]
Answer = 16 square blocks.

There are 16 square blocks in the shape.

I hope this helps.
6 0
3 years ago
Read 2 more answers
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
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