1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
quester [9]
1 year ago
6

Perform the following:-1/3 + 6/715/16 - 3/47/6x + -4/3y

Mathematics
1 answer:
Wittaler [7]1 year ago
6 0

SOLUTION

\begin{gathered} a\text{. }\frac{-1}{3}\text{ + }\frac{6}{7} \\  \\ \frac{-7+18}{21} \\  \\ \frac{11}{21} \end{gathered}

b.

\begin{gathered} \frac{15}{16}-\frac{3}{4} \\  \\ \frac{15-12}{16} \\  \\ \frac{3}{16} \end{gathered}

c.

\begin{gathered} \frac{7}{6x}+\frac{-4}{3y} \\  \\ \frac{7y-8x}{6xy} \end{gathered}

So we just have to find the LCM of the denominators, then we perform the rule of addition of fraction

You might be interested in
mary spends 40% of her monthly earnings on rent and 10% of the remaining amount on entertainment. If she spends $800 for rent, h
liraira [26]

Answer:

<em>$120</em>

Step-by-step explanation:

40% of the earnings is spent on rent.

The earnings is an unknown, so we call it x.

The rent is $800, so 40% of x equals $800.

40% * x = 800

0.4x = 800

x = 800/0.4

x = 2000

She earns $2000 per month.

After paying rent, the remaining amount is

$2000 - $800 = $1200

She spends 10% of the remaining amount on entertainment.

10% of $1200 = 10% * $1200 = 0.1 * $1200 = $120

5 0
3 years ago
Ben drinks tea at an incredible rate.He drinks 3 1/2 liters of tea every 2/3 of an hour.Ben drinks tea a constant rate.How many
vampirchik [111]

Answer:


Step-by-step explanation:

2/3 = 0.66

1 hour = 60

60 x 0.66 = 39.6 or 40  

In which, 60 - 40 = 20; so he only drinks 3 1/2 liters every 40 minutes.

He drinks 3 1/2 every hour.

3 0
3 years ago
How many real solutions does the equation y=12x-9x+4 have?
jek_recluse [69]

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     y-(12*x^2-9*x+4)=0 

Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span> y - (((22•3x2) - 9x) + 4) = 0 </span><span>Step  2  :</span><span>Equation at the end of step  2  :</span><span> y - 12x2 + 9x - 4 = 0 </span><span>Step  3  :</span>Solving a Single Variable Equation :

<span> 3.1 </span>    Solve  <span> <span>y-12x2+9x-4</span> </span> = 0 

In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.

3 0
2 years ago
Find the mean of the following data set. 8, 5, 15, 12, 10 12.5 10 14 50
cluponka [151]

Answer:

10

Step-by-step explanation:

8+5+15+12+10= 50 / 5 = 10

7 0
3 years ago
The answer <br> The answer
docker41 [41]

Answer:

10.21

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Other questions:
  • Ason buys a pizza for $\$15.59$. He also buys $6$ sodas. Each soda costs the same amount. He spends $\$23.33$ on the pizza and t
    10·1 answer
  • In an alloy of copper and tin, there is 85% of copper. How much of this alloy do you need in order to get 1 13/32 lb of tin?
    5·1 answer
  • What is the first quartile of the data set represented by the box plot shown below?
    13·1 answer
  • What are the x-intercept and y-intercept of the graph of y=−12x+4 ? Drag and drop your answers into the boxes. x-intercept: y-in
    10·1 answer
  • The slope of the line whose equation is x + y = 6 is: -1 1 6
    12·1 answer
  • F(x) = x3 - 2x2 + x - 2
    9·1 answer
  • Help me solve this problem please
    10·1 answer
  • The line a and the plane Pi have a common point O and the angle between the line and the plane is 60 degrees. If point A belongs
    13·1 answer
  • Carmen plans to paint the inside of her swimming pool before she fills it. The pool is a rectangular prism with a length of 20 f
    6·1 answer
  • Math!! please please helppp!!!
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!