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1 year ago

Workout the equation of the line wich has a gradient of 3 and passes through the piont (-1, 3)

1 answer:

Nutka1998 [239]1 year ago

7 0

The equation of the line which has a gradient of 3 and passes through the point; (-1, 3) as given in the task content is; y = 3x + 6.

<h3>What is the equation of the line which has a gradient of 3 and passes through (-1, 3)?</h3>

It follows from the task content that the equation of the line which is as described is to be determined.

It follows from the point-slope form equation of a straight line that;

(y - y1) = m (x - x1)

Therefore, in this scenario;

y - 3 = 3 (x - (-1))

y - 3 = 3x + 3

y = 3x + 6

Ultimately, the required equation is; y = 3x + 6.

Read more on equation of a line;

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What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)?

GrogVix [38]

First find the slope of the given line like this:
$5x + 2y = 12\\2y=-5x+12\\y=\frac{-5}{2}x+6$
If two lines are parallel, then they have the same slope, so the equation we are looking for is in the form:
$y=\frac{-5}{2}x+a$ and we have to find b using the given point like this:
Substitute x = -2 and y=4 in the above equation like this and solve for a:
$4=\frac{-5}{2}(-2)+a$
$4=5+a$
$a=4-5=-1$
The equation of the line is then the following:
$y=\frac{-5}{2}x-1.$

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Answer:

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PLZ HELP ME Use the distribute property to subtract and combine like terms <br> (5x)-(3x² + 3x)

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Step-by-step explanation:

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The median of the marks 10, 13, 3x-1, 3x+1, 18, 18 arranged in ascending order is

Lorico [155]

Answer:

a. Marks = 10, 13, 14, 16, 18, 18

b. mode = 18

c. Range = 8

Step-by-step explanation:

==>Given the following data set arranged in ascending order:

10, 13, 3x-1, 3x+1, 18, 18

Median = 15

==>Required:

a. Marks:

To get each marks, let's find the value of x since we know median to be 15.

10, 13, [3x-1, 3x+1], 18, 18

Our median in this even number of data set would be the average of the 2 middle values which would give us 15.

Thus, we have:

[(3x-1) + (3x+1)] ÷ 2 = 15

[3x-1 + 3x+1] ÷ 2 = 15

[3x+3x-1+1] ÷ 2 = 15

6x/2 = 15

Multiply 2 by both sides

6x = 30

Divide 6 by both sides

x = 5

Now let's plug in the value of x to get out marks:

10, 13, 3(5)-1, 3(5)+1, 18, 18

10, 13, 14, 16, 18, 18

b. Mode is the most appeared data value, which is 18

c. Range is the difference between the highest and lowest value = 18 - 10 = 8

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