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Leviafan [203]
1 year ago
8

Workout the equation of the line wich has a gradient of 3 and passes through the piont (-1, 3)

Mathematics
1 answer:
Nutka1998 [239]1 year ago
7 0

The equation of the line which has a gradient of 3 and passes through the point; (-1, 3) as given in the task content is; y = 3x + 6.

<h3>What is the equation of the line which has a gradient of 3 and passes through (-1, 3)?</h3>

It follows from the task content that the equation of the line which is as described is to be determined.

It follows from the point-slope form equation of a straight line that;

(y - y1) = m (x - x1)

Therefore, in this scenario;

y - 3 = 3 (x - (-1))

y - 3 = 3x + 3

y = 3x + 6

Ultimately, the required equation is; y = 3x + 6.

Read more on equation of a line;

brainly.com/question/6497976

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Given the graph below, what is the zero(s)?
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3 years ago
A triangle with vertices at A(0,0), B(0,4), and C(6,0) is dilated to yield a triangle with vertices at A(0,0), (B(0,10), and C (
dezoksy [38]

The required scale factor for the dialed triangle is given by SF= 6.28

A triangle with vertices at A(0,0), B(0,4), and C(6,0) is dilated to yield a triangle with vertices at A(0,0), (B(0,10), and C (C(15,0).

<h3>What is scale factor?</h3>

The scale factor is defined as the ratio of modified change in length to the original length.

Since, the height and base of the triangle is y coordinate of B and x coordinate of c is given by 4, 6
Area of triangle =1/2(base x height)
                         = 1/2 (4 x 6)
                         =   4.8
Similarly, for dilated triangle
Area of dilated triangle =  30

Now, scale factor(SF) = area of dilated triangle \ area of triangle
SF = 30/4.8
SF = 6.25

Thus, the required scale factor is SF = 6.25

 

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brainly.com/question/22312172

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4 0
2 years ago
Can you help me find length bc please!!!!
masya89 [10]

Remark

You are dealing with a right angle triangle. You can use one of Sin(x) Cos(x) or Tan(x). Since the Hypotenuse is involved and since you are given the adjacent side, Cos(71) is what you will need.

Solution

H = BC

Cos(x) = adjactent / hypotenuse

Cos(71) = 6.3 / H            Multiply both sides by H

H * Cos(71) = 6.3            Divide by Cos(71)

H = 6.3 / cos(71)             Cos(71) = 0.32557

H = 6.3 / 0.32557          Divide

H = BC = 19.351                       Answer

6 0
3 years ago
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