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Leviafan [203]
1 year ago
8

Workout the equation of the line wich has a gradient of 3 and passes through the piont (-1, 3)

Mathematics
1 answer:
Nutka1998 [239]1 year ago
7 0

The equation of the line which has a gradient of 3 and passes through the point; (-1, 3) as given in the task content is; y = 3x + 6.

<h3>What is the equation of the line which has a gradient of 3 and passes through (-1, 3)?</h3>

It follows from the task content that the equation of the line which is as described is to be determined.

It follows from the point-slope form equation of a straight line that;

(y - y1) = m (x - x1)

Therefore, in this scenario;

y - 3 = 3 (x - (-1))

y - 3 = 3x + 3

y = 3x + 6

Ultimately, the required equation is; y = 3x + 6.

Read more on equation of a line;

brainly.com/question/6497976

#SPJ1

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check the picture below.

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\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9


\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill

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