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2 years ago

Write numbers to make each line have the same sum

Mathematics

1 answer:

wlad13 [49]2 years ago

7 0

Answer:

There is nothing here?

Step-by-step explanation:

You might be interested in

Maria drove from Los Angeles (elevation 330 feet) to Death Valley (elevation –282 feet). What is the difference in elevation bet

motikmotik

Answer:

612 feet

Step-by-step explanation:

LA is located at 330 feet ABOVE SEA LEVEL

Death Valley is located 282 feet BELOW SEA LEVEL

We let the sea level be at 0 (consider a number line).

So,

LA would be at +330 feet

and

Death Valley would be at -282 feet

The elevation change between the two would be the difference:

330 - (-282) = 330 + 282 = 612 feet

The difference in elevation = 612 feet

3 0

3 years ago

I need help with my pre-calculus homework, please show me how to solve them step by step if possible. The image of the problem i

Anna [14]

We know that the law of sines states that:

$\frac{\sin\alpha}{a}=\frac{\sin\beta}{b}$

For simplicity, let:

$\beta=m\angle A_1BC$

In triangle A1BC this leads to:

$\begin{gathered} \frac{\sin31}{5}=\frac{\sin\beta}{6} \\ \sin\beta=\frac{6}{5}\sin31 \\ \beta=\sin^{-1}(\frac{6}{5}\sin31) \\ \beta=38.174 \end{gathered}$

Therefore:

$m\angle A_1BC=38.174$

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:

$m\angle CA_2B=180-38.174=141.826$

8 0

1 year ago

7/8 as a decimal<br><br> I got: .807 (repeating)

yan [13]

Answer:

the answer is .875

Step-by-step explanation:

u were close!! keep trying

8 0

3 years ago

A person has three times as many nickels as quarters. if the total face value of these coins is $4.40, how many of each type of

saul85 [17]

3 nickels and 1 quarter add to $0.40.
The person has 11 times that amount, so has 11 quarters and 33 nickels.

6 0

3 years ago

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago