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3 years ago

I don’t get this problem:// I’m so confused. I need help asap!!!

Mathematics

1 answer:

Ad libitum [116K]3 years ago

7 0

Answer:

y = -4/3x+7

Step-by-step explanation:

y=mx+b

b is the y-intercept (the point where the lines crosses the y-axis)

m is the gradient of the line

y = -4/3x+7

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Without solving the equation -3x+5 =44 tell whether the value of x is negative or positive

marshall27 [118]

Answer:

x= -13

The value of x is negative

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover

victus00 [196]

Answer:

Answer:

a. Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

b) Ending Inventory: Matrix D:

Hard Soft Plastic

San Francisco 400 4,800 3,000

Los Angeles 1,600 7,800 3,000

Step-by-step explanation:

a) Data and Calculations:

Stock on January 1: Matrix A

Hard Soft Plastic

San Francisco 1,000 3,000 6,000

Los Angeles 1,000 6,000 3,000

Sales in January: Matrix B

Hard Soft Plastic

San Francisco 700 1,200 2,000

Los Angeles 400 200 500

Restocking: Matrix C

Hard Soft Plastic

San Francisco 600 1,500 1,500

Los Angeles 500 500 500

Total Sales over the first 6 months =

Matrix B * 6 = Matrix B6

Sales in January: Matrix B

Hard Soft Plastic

San Francisco 700 1,200 2,000

Los Angeles 400 200 500

* 6

Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

Matrix C6 = Matrix C * 6

Restocking: Matrix C6

Hard Soft Plastic

San Francisco 3,600 9,000 9,000

Los Angeles 3,000 3,000 3,000

Inventory at the end of June =

Matrix A + Matrix C6 - Matrix B6

= Matrix D

Stock on January 1: Matrix A

Hard Soft Plastic

San Francisco 1,000 3,000 6,000

Los Angeles 1,000 6,000 3,000

Restocking: Matrix C6

Hard Soft Plastic

San Francisco 3,600 9,000 9,000

Los Angeles 3,000 3,000 3,000

Sales from January to June: Matrix B6

Hard Soft Plastic

San Francisco 4,200 7,200 12,000

Los Angeles 2,400 1,200 3,000

Ending Inventory: Matrix D:

Hard Soft Plastic

San Francisco 400 4,800 3,000

Los Angeles 1,600 7,800 3,000

3 0

3 years ago

A population has a mean of 300 and a standard deviation of 70. Suppose a sample of size 125 is selected and is used to estimate

Mrrafil [7]

Answer:

a: 0.8884

b: 0.9934

Step-by-step explanation:

We have µ = 300 and σ = 70. The sample size, n = 125.

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.8884

Next we want the probability of the sample mean to be within 17 units of the population mean, so we want the values from 283 to 317. We want to find

P(283 < x < 317)

We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.

We have P(283 < x < 317) = 0.9934

5 0

3 years ago

Solve the system of equations using matrices. Use the Gauss- Jordan elimination method And find a solution set

KATRIN_1 [288]

$\begin{gathered} x+y+z=4 \\ x-y-z=0 \\ x-y+z=8 \\ \text{The system using matrix is} \\ \begin{bmatrix}{1} & {1} & {1}, & {4} \\ {1} & {-1} & {-1,} & {0} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix}\rightarrow F2=F2-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {1} & {-1} & {1,} & {8}{}{}\end{bmatrix} \\ \rightarrow F3=F3-F1=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {-2} & {-2,} & {-4} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F2=-\frac{1}{2}F2 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {-2} & {0,} & {4}{}{}\end{bmatrix}\rightarrow F3=F3+2F2=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {2,} & {8}{}{}\end{bmatrix}\rightarrow F3=\frac{1}{2}F3 \\ =\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {1,} & {2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F2=F2-F3=\begin{bmatrix}{1} & {1} & {1}, & {4} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \rightarrow F1=F1-F3=\begin{bmatrix}{1} & {1} & {0}, & {0} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix}\rightarrow F1=F1-F2 \\ =\begin{bmatrix}{1} & {0} & {0}, & {2} \\ {0} & {1} & {0,} & {-2} \\ {0} & {0} & {1,} & {4}{}{}\end{bmatrix} \\ \text{Therefore, the solution is }x=2,\text{ y=-2 and z=4} \end{gathered}$

6 0

1 year ago

Two circles are concentric if they have the same center.

Tpy6a [65]

9514 1404 393

Answer:

(b) (x – 4)^2 + (y – 6)^2 = 16

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

You want the equation for a circle with center (4, 6) and radius 4. That equation is ...

(x -4)^2 +(y -6)^2 = 16

3 0

3 years ago