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worty [1.4K]
1 year ago
5

completa con las razones trigonométricas de cada triángulo rectángulo dado y encuentra el lado faltante aplicando el teorema de

Pitágoras

Mathematics
1 answer:
Rus_ich [418]1 year ago
4 0

primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a

a=\sqrt[]{hipotenusa^2-cateto^2}a=\sqrt[]{100^2-85^2}=52.68

a=52.68 m

teniendo el lado faltante podemos calcular las razones trigonometricas

\sin (55)=\frac{85}{100}=0.85\cos (55)=\frac{52.68}{100}=0.52\tan (55)=\frac{85}{52.68}=1.61

\csc (55)=\frac{100}{85}=1.17\sec (55)=\frac{100}{52.68}=1.89\cot (55)=\frac{52.68}{85}=0.61

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Answer:

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Step-by-step explanation:

Given

XZ=8x-18 and RZ=2x+5

XR=XZ-RZ

8x-18-2x+5

8x-2x-18+5

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2 years ago
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Step-by-step explanation:

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3 years ago
April sold 75 tickets to the school Christmas play and collected $495. If adult tickets cost $8 and children tickets were $5 how
Ostrovityanka [42]

40 adult tickets were sold and 35 children tickets were sold

<em><u>Solution:</u></em>

Let "a" be the number of adult tickets sold

Let "c" be the number of children tickets sold

Cost of 1 adult ticket = $ 8

Cost of 1 children ticket = $ 5

<em><u>Given that April sold 75 tickets to the school Christmas play and collected $495</u></em>

Number of tickets sold = 75

number of adult tickets sold + number of children tickets sold = 75

a + c = 75 ----- eqn 1

<em><u>Given that April collected $495</u></em>

Thus we can frame a equation as:

number of adult tickets sold x Cost of 1 adult ticket + number of children tickets sold x Cost of 1 children ticket = $ 495

a \times 8 + c \times 5 = 495

8a + 5c = 495 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

From eqn 1,

a = 75 - c ---- eqn 3

Substitute eqn 3 in eqn 2

8(75 - c) + 5c = 495

600 - 8c + 5c = 495

-3c = 495 - 600

-3c = - 105

<h3>c = 35</h3>

Substitute c = 35 in eqn 3

a = 75 - 35

<h3>a = 40</h3>

Thus 40 adult tickets were sold and 35 children tickets were sold

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3 years ago
About 7/10 of the surface of the earth is covered with water. Express this as an equivalent fraction with 100 as the denominator
larisa [96]

Answer:

70/100

Step-by-step explanation:

Surface of the earth covered with water = 7/10

Equivalent fraction of 7/10 with 100 as the denominator = 70/100

This means 70% of the earth surface is covered with water

Percentage covered with land = Total percentage - percentage covered with water

= 100/100 - 70/100

= 100-70/100

= 30/100

Percentage covered with land = 30%

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3 years ago
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