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slava [35]
4 years ago
15

Need help on this can somewe me help me pleasere

Mathematics
2 answers:
maw [93]4 years ago
8 0
The answer is mpn=mqn because both side should be quite equal so I would say the last one is the closest
Luda [366]4 years ago
4 0
MPN = MQN Should be the Answer
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A gymnast trains for 4 months for her competition how many weeks did she train.
BaLLatris [955]

Answer:

16 weeks

Step-by-step explanation:

Assuming that each month is around 4 weeks, multiply that number by 4 months and you will get 16 weeks in total.

5 0
3 years ago
Read 2 more answers
Solve: -6____=-8 ; what goes on the blank spot?
grin007 [14]
There are at least two different things that could go in
the blank spot and make the equation a true statement.

It could be " - 2 " .

It could be " · 4/3 " .

It could be " + 2 cos(π) "

etc.
7 0
3 years ago
Which represents the solution(s) of the equation x2 = 289?
sergeinik [125]

Answer:

B) x = +/- 17

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Maths question please help !! thank u :)​
nikdorinn [45]

Answer:

1350m

Step-by-step explanation:

Let the distance ran by Denise, Farah and Elaine be D, F and E meters respectively.

From the given information,

D= ⅔(E +F) -----(1)

E= ½(D +F) -----(2)

Let's get rid of the fraction so the equations are much easier to work with.

From (1):

3D= 2(E +F) <em>(Multiply both sides by 3)</em>

3D= 2E +2F -----(3) <em>(</em><em>Expand</em><em>)</em>

From (2):

2E= D +F -----(4)

Substitute (4) into (3):

3D= D +F +2F

3D -D= 3F

2D= 3F

Given that Farah ran 360m, F= 360.

2D= 3(360)

2D= 1080

D= 1080 ÷2

D= 540

2E= D +F

2E= 540 +360

2E= 900

E= 900 ÷2

E= 450

Total distance the 3 girls ran

= D +F +E

= 540 +360 +450

= 1350m

Alternatively, you could start by substituting F= 360 to equations (1) and (2).

6 0
3 years ago
You are building a new house on a cartesian plane whose units are measured in miles.
Wewaii [24]
We first find the shortest distance between the point (2, 0) and the curve y=\sqrt{16x^2+5x+16}
Let the point on the curve for which the line making the shortest distance be (x, y), then
d= \sqrt{(x-2)^2+(y-0)^2} = \sqrt{(x-2)^2+y^2}
But, y=\sqrt{16x^2+5x+16}
Therefore,
d=\sqrt{(x-2)^2+(\sqrt{16x^2+5x+16})^2}=\sqrt{x^2-4x+4+16x^2+5x+16}\\= \sqrt{17x^2+x+20}
For minimum d(d)/dx = 0
\frac{d(d)}{dx} = \frac{34x+1}{2 \sqrt{17x^2+x+20}} =0\\34x+1=0\\x=- \frac{1}{34}
Therefore, shortest distance is
d= \sqrt{17(- \frac{1}{34})^2- \frac{1}{34}+20 } = \sqrt{ \frac{1359}{68}} =4.47 \ miles
Since it costs 400 dollars per mile, 4.47 miles will cost 4.47 x 400 = $1,788.20
7 0
3 years ago
Read 2 more answers
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