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fenix001 [56]
3 years ago
10

7-(30-2) divided by 7 equals?

Mathematics
2 answers:
AleksandrR [38]3 years ago
8 0

Answer:

first, you have to subtract the numbers in the parentheses

(30-2) = 28

So, your equation is now

7 - 28

And subtract that and you get -21.

Now you want to take -21 and divide it by 7

And you get -3.

I hope this helps! Have a nice day!!

~abelxoconda <3

dybincka [34]3 years ago
6 0

Answer:

Step-by-step explanation:

first, do 30-2 to get 28. 7-28 is -21. -21/7 is -3

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For a direct variation, f(x) = kx. Therefore, for f(x) = 30x, constant of variation (k) = 30.
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Solve the equation
denpristay [2]

Answer:B

Step-by-step explanation:

4x2 =121

4x2-121=0

using the general formula

[-b( +/-) √b2-4ac]/2a

a=4, b= 0, c=-121

x= [0 ( +/-)√02-(4*4*-121)]/2.4

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Simplify the expression.<br> 3\5x + 19 - 3/20x -7
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Answer:

9/20 x+12

Step-by-step explanation:

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Finding diagonal sum

\\ \sf\longmapsto 0.7+1.0+1.3

\\ \sf\longmapsto 0.7+2.3

\\ \sf\longmapsto 3.0

#b

Observing the square

  • x=0.9
  • y=0.6

\\ \sf\longmapsto xy=0.9(0.6)

\\ \sf\longmapsto xy=0.54

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Need help asap, thanks!!!ヾ(⌐■_■)ノ♪
Lelu [443]

Step-by-step explanation:

the probability of making one shot is 75% or 0.75 or 3/4.

the probability to make 2 shots is then

3/4 × 3/4 = 9/16 = 0.5625

and so on.

the probability to miss 1 shot is then 25% or 0.25 or 1/4.

the probability to make at least 4 out of 5 shots is the sum of the probability to make all 5 shots plus the probability to make 4 shots.

or the probability to miss 0 plus the probability to miss 1 shot.

anyway, we can go with the positive approach. it seems to be the same complexity as the negative approach.

the probability to make all 5 shots is

(3/4)⁵ = 3⁵/4⁵ = 243 / 1024 = 0.237304688...

the probability to e.g make the first 4 shots and miss the 5th is

(3/4)⁴×1/4 = 3⁴/4⁵ = 81 / 1024 = 0.079101563...

how many possibilities do we have to make 4 out of 5 shots ?

there is no repetition, and the sequence inside the "picked" 4 does not matter, so we need combinations :

C(5,4) = 5! / (4! × (5-4)!) = 5

so, the probability to make exactly 4 out 5 shots is

81/1024 × 5 = 405/1024 = 0.395507813...

and the total probability to make at least 4 shots is

243/1024 + 405/1024 = 648/1024 = 81/128 = 0.6328125

to control,

this plus making exactly 3 plus exactly 2 plus exactly 1 plus none must be the probability 1 (as there is no other possible outcome).

making 3 :

(3/4)³×(1/4)² = 3³/4⁵ = 27/1024

C(5,3) = 5×2 = 10

270/1024

making 2 :

3²/4⁵ = 9/1024

C(5,2) = 5×2 = 10

90/1024

making 1 :

3/1024

C(5,1) = 5

15/1024

making 0 :

1/1024

in sum

(270+90+15+1)/1024 = 376/1024

plus the 648/1024 = 1024/1024 = 1

correct.

4 0
2 years ago
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