(a): This is an elimination reaction. The reaction proceeds in 3 steps; Step 1: Protonation of alcohol, step 2: Loss of leaving group, and step 3: Deprotonation to form an alkene. Elimination (E1) reaction dominates than substitution (SN1) reaction because the formed HSO4- anion is a poor nucleophile and tends not to add to the carbocation intermediate formed. Hence the product formed is I, is trans.
(b) This is a dihydroxylation of the alkenes reaction. A catalytic amount of OsO4 is used along with an oxidizing agent, which oxidizes the reduced osmium(VI) into osmium(VIII) to regenerate the catalyst. The reaction proceeds in 2 steps; Step 1: Cis addition of OsO4 to double bond and form 4 member cyclic osmate ester. Step 2: Hydrolysis of the intermediate to 1.2-diol. Hence the product formed is II, is cis.
(c) This is hydroboration - oxidation reaction. The reaction proceeds through the addition of H- on the more substituted carbon and BH2 on the less substituted carbon of the double bond. The reaction is a syn addition. Hence the product formed is III.
(d) This a reduction reaction where carboxylic acid (-COOH) is reduced to 1o alcohol (-CH2OH). Hence the formed product is IV.
Stereochemistry, a subdiscipline of chemistry, involves the take a look at the relative spatial association of atoms that form the shape of molecules and their manipulation.
The observation of stereochemistry specializes in stereoisomers, which by means of definition have an equal molecular method and series of bonded atoms (constitution), however, differ within the three-dimensional orientations of their atoms in space. for that reason, it's also referred to as 3-d chemistry three-dimensionality.
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Each of the following reactions has been reported in the chemical literature. Predict the product in each case, showing stereochemistry where appropriate.
Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,
Compound's mass,
= 0.4647 g
Let the compound's formula will be:
Combustion's general equation will be:
⇒
On putting the estimated values, we get
⇒
⇒
⇒
⇒
Now,
x : y : z =
=
=
=
So that the empirical formula seems to be "C₃H₆O₂".
This is an incomplete question, here is a complete question.
The balanced chemical reaction is:
In another experiment, if 80 molecules react with 104
molecules. How many
molecules will be produced which reactant will be used up in the reaction.
Answer : The number of molecules of will be, 52 molecules and
reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.
Explanation :
The balanced chemical reaction is:
First we have to determine the limiting reagent.
From the balanced reaction we conclude that,
As, 8 molecules of react with 6 molecule of
So, 104 molecules of react with
molecule of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the molecules of
From the reaction, we conclude that
As, 8 molecules of react to give 4 molecules of
So, 104 molecules of react to give
molecules of
Hence, the number of molecules of will be, 52 molecules and
reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.